您将需要递归:
CREATE TABLE f(id int, s char);
INSERT INTO f(id) VALUES
(10);
CREATE TABLE m(id int, old_id int, new_id int, type char, s char, d date);
INSERT INTO m (id, old_id, new_id, type, d, s) VALUES
(2, 20, NULL, 'U', '2018-01-01', 'a'),
(3, 10, 20, 'R', '2018-01-01', NULL),
(4, 10, NULL, 'U', '2018-01-01', 'b'),
(5, 20, NULL, 'U', '2018-01-01', 'c'),
(6, 30, NULL, 'U', '2018-01-01', 'd'),
(7, 20, 30, 'R', '2018-01-01', NULL),
(8, 30, NULL, 'U', '2018-01-01', 'e'),
(9, 40, NULL, 'U', '2018-01-01', 'f');
WITH cte AS (
SELECT *, 1 AS lvl
FROM m AS base
WHERE old_id = (SELECT id FROM f)
UNION ALL
SELECT curr.*, lvl + 1
FROM m AS curr
INNER JOIN cte AS prev ON prev.type = 'R' AND curr.old_id = prev.new_id
)
SELECT *
FROM cte
ORDER BY lvl, CASE type WHEN 'U' THEN 1 WHEN 'R' THEN 2 END
结果:
| id | old_id | new_id | type | s | d | lvl |
|----|--------|--------|------|---|------------|-----|
| 4 | 10 | | U | b | 01/01/2018 | 1 |
| 3 | 10 | 20 | R | | 01/01/2018 | 1 |
| 2 | 20 | | U | a | 01/01/2018 | 2 |
| 5 | 20 | | U | c | 01/01/2018 | 2 |
| 7 | 20 | 30 | R | | 01/01/2018 | 2 |
| 6 | 30 | | U | d | 01/01/2018 | 3 |
| 8 | 30 | | U | e | 01/01/2018 | 3 |
-
这个
基础
递归CTE的一部分包含所有包含10的行
-
然后选择
R
行从
普雷夫
迭代以获取新ID并从主表中选择行,其中旧ID=新ID
-
最后,按照CTE中处理行的顺序对行进行排序。