将4个文件合并为1个具有不同列的文件

t1.rg contains Fri Aug 3 19:48:58 MYT 2018 t2.rg contains 27 t3.rg contains A-inter-rt01 t4.rg contains 32166 我试过这个: pr -mts t1.rg t3.rg t2.rg t4.rg

但结果是这样的:

`Fri Aug 32166:48:58 MYT 2018    A-inter-rt01 27`

value1=$(cat t1.rg) value2=$(cat t3.rg) value3=$(cat t2.rg) value4=$(cat t4.rg)

`value5=$(paste <printf "%s" "$value1" <printf "%s" "$value2" <printf "%s" 
"$value3" <printf "%s" "$value4")
 `

但对我来说这是多么的有效。

 `Fri Aug  3 19:48:58 MYT 2018 |  27   | A-inter-rt01  | 32166`

我对脚本很陌生,请帮忙