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输出流未转换为字符串变量

outputstream runnable byte multithreading java

StealthRT · 技术社区 · 5 年前

输出流 把它串成一个字符串,这样我就可以用我的逻辑更好地检查它。

工作得很好 如果我只是想写致慰问仅此而已。不过,我想把它储存起来输出一串 .

public static void main(String[] args) throws IOException {
    Process p;

    try {
        p = Runtime.getRuntime().exec("cmd");
        new Thread(new SyncPipe(p.getErrorStream(), System.err)).start();
        new Thread(new SyncPipe(p.getInputStream(), System.out)).start();
        PrintWriter stdin = new PrintWriter(p.getOutputStream());
        stdin.println("cd C:/Local Apps/xxx/xxx/xxxx/eclipse");
        stdin.println("lscm login -r https://xxxx.xxxx.xxxx.xxxx:9443/ccm -n xxxx.xxxx.xxx.xxxx -u itsme -P gr^34dbtfgt7y");
        stdin.close();

        p.waitFor();
    } catch (Exception e) {
        e.printStackTrace();
    }
}

}

class SyncPipe implements Runnable {
    public SyncPipe(InputStream istrm, OutputStream ostrm) {
        istrm_ = istrm;
        ostrm_ = ostrm;
    }

    public void run() {
        try {
            final byte[] buffer = new byte[1024];

            for (int length = 0; (length = istrm_.read(buffer)) != -1;) {
                ostrm_.write(buffer, 0, length);                    
            }
        } catch (Exception e) {
            e.printStackTrace();
        }
    }

    private final OutputStream ostrm_;
    private final InputStream istrm_;
}

ostrm_.write(buffer, 0, length);

我在谷歌上找到了各种各样的东西:

String string = new String(ostrm_.toString());
System.out.println(string);

String string = new String(ostrm_.toString("UTF-8"));
System.out.println(string);

final PrintStream blah = new PrintStream(ostrm_);
final String string = blah.toString();
System.out.println(string);

String blah = ostrm_.toString();
System.out.println(string);

byte[] blah = buffer;
String string = blah.toString();

输出流写入程序 但是,我又一次似乎无法让它工作。所以,如果一个Java大师能帮助我解决这个看起来很容易却很难解决的问题,那就太好了。。。。

更新1 后备箱和发动机罩:

4 回复 | 直到 5 年前

boot-and-bonnet 5 年前

你可以用 readAllBytes() String 使用默认字符集:

System.out.println(new String(istrm_.readAllBytes()));

madhepurian 5 年前

请试试这个:

byte[] blah = buffer;
String string = new String(blah);

StealthRT 5 年前

String line;
BufferedReader reader = new BufferedReader(new InputStreamReader(istrm_));

while ((line = reader.readLine()) != null) {
    System.out.println(line);
}

Andreas dfa 5 年前

你的代码做事情的方式很难。要在特定工作目录中运行命令并将输出发送到控制台,请使用 ProcessBuilder inheritIO() .

问题中的所有代码都可以简化为:

public static void main(String[] args) throws IOException {
    new ProcessBuilder("cmd", "/c",
                       "lscm", "login",
                       "-r", "https://xxxx.xxxx.xxxx.xxxx:9443/ccm",
                       "-n", "xxxx.xxxx.xxx.xxxx",
                       "-u", "itsme",
                       "-P", "gr^34dbtfgt7y")
            .directory(new File("C:/Local Apps/xxx/xxx/xxxx/eclipse"))
            .inheritIO()
            .start()
            .waitFor();
}

要将命令的所有输出收集到一个字符串中,首先要通过调用 redirectErrorStream(true) ,然后将输出收集到 String 使用适当的字符集。

Charset ,因为这可能是命令输出的内容。

String[] command = {
        "cmd", "/c",
        "lscm", "login",
        "-r", "https://xxxx.xxxx.xxxx.xxxx:9443/ccm",
        "-n", "xxxx.xxxx.xxx.xxxx",
        "-u", "itsme",
        "-P", "gr^34dbtfgt7y" };
Process p = new ProcessBuilder(command)
        .directory(new File("C:/Local Apps/xxx/xxx/xxxx/eclipse"))
        .redirectErrorStream(true) // stderr > stdout
        .start();
p.getOutputStream().close(); // stdin < NUL
String output;
try (InputStream in = p.getInputStream()) {
    output = new String(in.readAllBytes());
}
int errorCode = p.waitFor();

System.out.print(output);
if (errorCode != 0)
    System.out.println("Program terminated with error code " + errorCode);

上面的代码是针对Java9+的。对于Java 7+,获取 output

try (InputStream in = p.getInputStream()) {
    ByteArrayOutputStream bytes = new ByteArrayOutputStream(1024);
    byte[] buf = new byte[1024];
    for (int len; (len = in.read(buf)) > 0; )
        bytes.write(buf, 0, len);
    output = bytes.toString();
}