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禁用外键约束,仍然不能截断表?(SQL Server 2005)

  •  26
  • larryq  · 技术社区  · 15 年前

    我有一个名为px_子级的表,它在px_父级上有一个外键。我想暂时禁用这个fk约束,以便截断px_父级。不过,我不确定情况如何。

    我试过这些命令

    ALTER TABLE PX_Child NOCHECK CONSTRAINT ALL
    
    ALTER TABLE PX_Parent NOCHECK CONSTRAINT ALL
    
    (truncate commands)
    
    ALTER TABLE PX_Child CHECK CONSTRAINT ALL
    
    ALTER TABLE PX_Parent CHECK CONSTRAINT ALL
    

    但truncate仍然告诉我,由于外键约束,它无法截断px_父级。我环顾了整个网络,似乎找不到我做错了什么,对这个问题的基本性质感到抱歉。

    4 回复  |  直到 15 年前
        1
  •  39
  •   bobs    15 年前

    如果有任何外键引用该表(包括禁用的约束),则不能截断该表。您要么需要删除外键约束,要么使用 DELETE 命令。

        2
  •  13
  •   RJB    10 年前

    有一种更简单的方法。我也面临同样的问题,找到了解决办法: https://www.mssqltips.com/sqlservertip/3347/drop-and-recreate-all-foreign-key-constraints-in-sql-server/

    如果只在数据库中运行此查询,它将生成存储过程之前/之后需要包含的T-SQL,以便删除并恢复任何外键约束。

    不要担心试图理解这个查询本身。

    CREATE TABLE #x -- feel free to use a permanent table
    (
      drop_script NVARCHAR(MAX),
      create_script NVARCHAR(MAX)
    );
    
    DECLARE @drop   NVARCHAR(MAX) = N'',
            @create NVARCHAR(MAX) = N'';
    
    -- drop is easy, just build a simple concatenated list from sys.foreign_keys:
    SELECT @drop += N'
    ALTER TABLE ' + QUOTENAME(cs.name) + '.' + QUOTENAME(ct.name) 
        + ' DROP CONSTRAINT ' + QUOTENAME(fk.name) + ';'
    FROM sys.foreign_keys AS fk
    INNER JOIN sys.tables AS ct
      ON fk.parent_object_id = ct.[object_id]
    INNER JOIN sys.schemas AS cs 
      ON ct.[schema_id] = cs.[schema_id];
    
    INSERT #x(drop_script) SELECT @drop;
    
    -- create is a little more complex. We need to generate the list of 
    -- columns on both sides of the constraint, even though in most cases
    -- there is only one column.
    SELECT @create += N'
    ALTER TABLE ' 
       + QUOTENAME(cs.name) + '.' + QUOTENAME(ct.name) 
       + ' ADD CONSTRAINT ' + QUOTENAME(fk.name) 
       + ' FOREIGN KEY (' + STUFF((SELECT ',' + QUOTENAME(c.name)
       -- get all the columns in the constraint table
        FROM sys.columns AS c 
        INNER JOIN sys.foreign_key_columns AS fkc 
        ON fkc.parent_column_id = c.column_id
        AND fkc.parent_object_id = c.[object_id]
        WHERE fkc.constraint_object_id = fk.[object_id]
        ORDER BY fkc.constraint_column_id 
        FOR XML PATH(N''), TYPE).value(N'.[1]', N'nvarchar(max)'), 1, 1, N'')
      + ') REFERENCES ' + QUOTENAME(rs.name) + '.' + QUOTENAME(rt.name)
      + '(' + STUFF((SELECT ',' + QUOTENAME(c.name)
       -- get all the referenced columns
        FROM sys.columns AS c 
        INNER JOIN sys.foreign_key_columns AS fkc 
        ON fkc.referenced_column_id = c.column_id
        AND fkc.referenced_object_id = c.[object_id]
        WHERE fkc.constraint_object_id = fk.[object_id]
        ORDER BY fkc.constraint_column_id 
        FOR XML PATH(N''), TYPE).value(N'.[1]', N'nvarchar(max)'), 1, 1, N'') + ');'
    FROM sys.foreign_keys AS fk
    INNER JOIN sys.tables AS rt -- referenced table
      ON fk.referenced_object_id = rt.[object_id]
    INNER JOIN sys.schemas AS rs 
      ON rt.[schema_id] = rs.[schema_id]
    INNER JOIN sys.tables AS ct -- constraint table
      ON fk.parent_object_id = ct.[object_id]
    INNER JOIN sys.schemas AS cs 
      ON ct.[schema_id] = cs.[schema_id]
    WHERE rt.is_ms_shipped = 0 AND ct.is_ms_shipped = 0;
    
    UPDATE #x SET create_script = @create;
    
    PRINT @drop;
    PRINT @create;
    
    /*
    EXEC sp_executesql @drop
    -- clear out data etc. here
    EXEC sp_executesql @create;
    */
    

    生成一组:

    ALTER TABLE [dbo].[Whatever] DROP CONSTRAINT....
    --
    ALTER TABLE [dbo].[Whatever] ADD CONSTRAINT....
    
        3
  •  5
  •   Paul Groke Chronial    15 年前

    即使禁用了约束,SQL Server也不会允许您在约束存在时截断表。 删除约束并在截断表后重新创建它。 或者只需删除并重新创建表,以应用程序中更容易执行的操作为准。

        4
  •  1
  •   BJ Coder    7 年前

    当外键约束时,没有这样的选项来截断表,但是我们可以使用类似的技巧

     ALTER TABLE [dbo].[table2] DROP CONSTRAINT [FK_table2_table1]
        GO
        truncate table [table1]
    GO
        ALTER TABLE [dbo].[table2]  WITH CHECK ADD  CONSTRAINT [FK_table2_table1] FOREIGN KEY([FKId])
        REFERENCES [dbo].[table1] ([ID])
        GO
    
        ALTER TABLE [dbo].[table2] CHECK CONSTRAINT [FK_table2_table1]
        GO