在测试完成之前不要等待超时

我有一个测试,等待一个异步函数,然后等待一个超时,然后等待另一个异步函数。

it('runs a snipe successfully', async () => {
      const exitCode = await john.chat.sendMoneyInChat(channel.topicName, channel.name, "0.01", botUsername);
      console.log('timeout?')
      await timeout(3000);
      console.log('timeout!');
      console.log('running bal check')
      let values;
      const nbl = await croupier.checkWalletBalance(process.env.CROUPIER_RINGO_USERNAME);
      expect(nbl).toEqual(123);
})

基于我的控制台。日志输出 afterAll 拆卸过程在安装完成后立即开始 timeout? 日志声明。换句话说,我不明白“ timeout! “在控制台日志中,我看到afterAll teardown中的console.log语句。

有什么好处?

编辑:

多亏@Metalmi的帮助,我修复了一个bug。现在我的代码是:

  it('runs a snipe successfully', async () => {
        jest.useFakeTimers()
        const exitCode = await john.chat.sendMoneyInChat(channel.topicName, channel.name, "0.01", botUsername);
        console.log('timeout?')
        jest.advanceTimersByTime(20000)
        console.log('timeout.');
        console.log('running bal check')
        let values;
        const nbl = await croupier.checkWalletBalance(process.env.CROUPIER_RINGO_USERNAME);
        expect(nbl).toEqual(123);        
  });

以下是checkWalletBalance功能:

  public checkWalletBalance(username: string): Promise<any> {
      let balance: number = 0;
      const self = this;
      return new Promise(async (resolve) => {
        try {
          const acct = await self.bot1.wallet.lookup(username);
          console.log("acct", acct);
          const balances = await self.bot2.wallet.balances(acct.accountId);
          console.log("balances", balances);
          balances.forEach((acctDetail) => {
            console.log(acctDetail.balance[0].amount);
            balance += parseFloat(acctDetail.balance[0].amount);
          });
          resolve(balance);
        } catch (e) {
          console.log(e);
          throw e;
        }

      });
    }

我猜在Promise中使用异步函数会有一些问题?

笑话在控制台前就开始了。日志(“acct”,acct)发生在 checkWalletBalance ,所以还是有问题。