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如何将带有数组的JSON解析为对象

json arrays c#

Bagzli · 技术社区 · 7 年前

考虑以下JSON:

{
  "0": {
    "id": "1",
    "email": "someemail@test.com",
    "tstamp": "2019-01-21 11:19:48",
    "times": "2",
    "tstamp_iso": "2019-01-21T12:19:48-05:00"
  },
  "1": {
    "id": "2",
    "email": "someotheremail@test.com",
    "tstamp": "2019-01-21 11:25:48",
    "times": "2",
    "tstamp_iso": "2019-01-21T12:25:48-05:00"
  },
  "result_code": 1,
  "result_message": "Success!",
  "result_output": "json"
}

不过,我正试图将该数据转换为C对象,但我不确定如何处理数组值。 0 , 1 它的名称而不是嵌套在数组中,如果有20个结果,它将一直持续到20个。 我无法更改JSON数据。

我走了这么远:

[JsonObject]
public class FirstObject
{
    [JsonProperty(PropertyName = "id")]
    public string Id { get; set; }

    [JsonProperty(PropertyName = "email")]
    public string Email { get; set; }

    [JsonProperty(PropertyName = "tstamp")]
    public string TimeStamp { get; set; }

    [JsonProperty(PropertyName = "times")]
    public string Times { get; set; }

    [JsonProperty(PropertyName = "tstamp_iso")]
    public string TimeStampIso { get; set; }
}

[JsonObject]
public class SecondObject
{
    public FirstObject[] FirstObjects { get; set; }

    [JsonProperty(PropertyName = "result_code")]
    public string ResultCode { get; set; }

    [JsonProperty(PropertyName = "result_message")]
    public string ResultMessage { get; set; }

    [JsonProperty(PropertyName = "result_output")]
    public string ResultOutput { get; set; }
}

我不明白的是如何将FirstObjects映射到0,1,…20岁。我希望有一个更好的方法,比写下20次和设置名称为0,或1,等等…

1 回复 | 直到 7 年前

Vladimir P. 7 年前

using Newtonsoft.Json;
using Newtonsoft.Json.Linq;
using System;
using System.Collections.Generic;

namespace ConsoleApp2
{
    class Program
    {
        const string json = @"{
                                  ""0"": {
                                    ""id"": ""1"",
                                    ""email"": ""someemail@test.com"",
                                    ""tstamp"": ""2019-01-21 11:19:48"",
                                    ""times"": ""2"",
                                    ""tstamp_iso"": ""2019-01-21T12:19:48-05:00""
                                  },
                                  ""1"": {
                                    ""id"": ""2"",
                                    ""email"": ""someotheremail@test.com"",
                                    ""tstamp"": ""2019-01-21 11:25:48"",
                                    ""times"": ""2"",
                                    ""tstamp_iso"": ""2019-01-21T12:25:48-05:00""
                                  },
                                  ""result_code"": 1,
                                  ""result_message"": ""Success!"",
                                  ""result_output"": ""json""
                              }";

        static void Main(string[] args)
        {
            JObject o = JObject.Parse(json);

            List<FirstObject> l = new List<FirstObject>();

            int c = 0;

            while (o[$"{c}"] != null)
            {
                FirstObject fo = o[$"{c++}"].ToObject<FirstObject>();
                l.Add(fo);
            }

            SecondObject so = JsonConvert.DeserializeObject<SecondObject>(json);

            so.FirstObjects = l.ToArray();

            Console.ReadKey();
        }
    }
}