代码之家 › 专栏 › 技术社区 › Cyberpks

如何在Android中获取EditText的更新值

android-asynctask android

Cyberpks · 技术社区 · 12 年前

我是android的新手,在android应用程序中使用web服务的基本屏幕上工作。

我正在使用 AsyncTask 并从web服务获取结果。在显示返回值之前,它工作正常。显示 Toast 点击消息,我得到旧值 TextView resultReturned

public class TestPost extends Activity{

private TextView result = null;

@Override
protected void onCreate(Bundle savedInstanceState) {
    // TODO Auto-generated method stub
    super.onCreate(savedInstanceState);
    setContentView(R.layout.my_screen);
    result = (TextView)findViewById(R.id.resultReturned);


    Button submit = (Button)findViewById(R.id.btnSubmit);

    submit.setOnClickListener(new View.OnClickListener() {

        @Override
        public void onClick(View v) {

            String[] strPost = new String[]{"value1", "value2"};
            SendAsyncRequest asyncSend = new SendAsyncRequest();
            asyncSend.execute(strPost);
            // ResultView retains old value and gets correct value on second click
            String returned = result.getText().toString();
            Toast.makeText(getApplicationContext(), returned, Toast.LENGTH_LONG).show();    
        }
    }); 
  }

public class SendAsyncRequest extends AsyncTask<String, Void, String>{
    private String fetchedData = "";
    @Override
    protected String doInBackground(String... params  ) {
        // perform async task
        return fetchedData;
    }
    @Override
    protected void onPostExecute(String result) {
            setReturedValue(result);
    }

}
private void setReturedValue(String data){
    result.setText(data);
}

那么,如何获取TextView的更新文本值?

2 回复 | 直到 12 年前

RajaReddy PolamReddy 12 年前

AsyncTask需要时间从请求中获取响应,在postExecute()方法中显示toast消息,就像这样,然后从onclick中删除。

@Override
protected void onPostExecute(String result) {
    Toast.makeText(getApplicationContext(), result, Toast.LENGTH_LONG).show();  
}

-1

Ved 12 年前

试试这个

submit.setOnClickListener(new View.OnClickListener() {

    @Override
    public void onClick(View v) {

        String[] strPost = new String[]{"value1", "value2"};
        SendAsyncRequest asyncSend = new SendAsyncRequest();
        asyncSend.execute(strPost);
        // ResultView retains old value and gets correct value on second click
        String jsonResult;
        try {
            jsonResult=asyncSend.get();

        } catch (InterruptedException | ExecutionException e) {
            e.printStackTrace();
        }

        Toast.makeText(getApplicationContext(), jsonResult, Toast.LENGTH_LONG).show();    
        }
});

并将Json字符串返回 doInBackground() .