swal破坏功能问题

我有swal函数的工作代码,但当我单击取消而不执行时,它将进入我不想进行的ajax调用

$(document).on('click','.addon',function() {
    Swal.fire({
      title: 'Provide Your Email Address',
      html: `<input type="email" name="emailaddress" id="emailaddress">
      `,
      confirmButtonText: 'Yes',
      showCancelButton:true,
      focusConfirm: false,
      allowOutsideClick:false,
      preConfirm: () => {
        const emailaddress = Swal.getPopup().querySelector('#emailaddress').value;
        if (!emailIsValid(emailaddress)) {
          Swal.showValidationMessage(`Please enter correct Email`)
        }
        return { emailaddress: emailaddress }
      },
      didDestroy: () => {
        $(this).prop('checked',false);
        return; - if i cancel, it should just quit and not go into tthen, 
      }
    }).then((result) => {
        var data = 'emailaddress=' + Swal.getPopup().querySelector('#emailaddress').value
        $.ajax({
          url: 'submission.cfm',
          data: data,
          type: 'POST',
          success: function(data) {
              var sdata = jQuery.parseJSON(data);
              if($.trim(sdata.status) == 1) {
                  swal.fire({
                      title:"Cool",
                      text: sdata.message,
                      type:"success",
                      confirmButtonText: 'OK'
                  }).then(() => {
                      window.location.reload();
                  });
              }else {
                  var err = sdata.message;
                  swal.fire("Oops...", err, "error");
              }
          }
      });
    })
  });

上面的代码可以工作,但当我单击取消时,它仍然会进入ajax,但我不想让它进入那里,我错过了什么吗