jpa findallby*使用长id而不是实体

我只是不想做:

myEntity = findById(Long id)
findAllByEntityAnd*(MyEntity myEntity, *)

相反,我想做的是:

findAllByEntityAnd*(Long entityId, *)

有什么东西我错过了实现我想要的,或者我只是不能直接实现它?

谢谢你的帮助~

当我尝试的时候,春天提醒我:

java.lang.IllegalArgumentException: Could not create query metamodel for method public abstract java.util.List com.worksap.morphling.raptor.dump.thread.dao.ThreadDoRepository.findAllByDumpDoAndLocksWaitingContains(java.lang.Long,java.lang.String)!

这是我的桌子供你参考:

@Data
@Builder
@Entity
@Table(name = "thread_info")
@AllArgsConstructor
@NoArgsConstructor
public class ThreadDo implements Serializable {
    private static final long serialVersionUID = -1L;
    String name;
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private Long id;
    @ManyToOne
    @JoinColumn(name = "thread_dump_id")
    @JsonIgnore
    private ThreadDumpDo dumpDo;

    ...
}

@Data
@Builder
@Entity
@Table(name = "thread_dump")
@AllArgsConstructor
@NoArgsConstructor
public class ThreadDumpDo implements Serializable {
    private static final long serialVersionUID = -1L;

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private Long id;

    @OneToMany(
            mappedBy = "dumpDo",
            cascade = CascadeType.ALL,
            orphanRemoval = true
    )
    private List<ThreadDo> threadDoList;
}

然后我有一个 ThreadDoRepository 想找到 threadDos 直接这样:

List<ThreadDo> findAllByDumpDoAndLocksWaitingContains(Long dumpId, String lockWaiting);

我可以通过 @Query 如下所述,但我真的认为它很难看,因为它很容易解释(我想)。

@Query(value = "select * from thread_info t where t.thread_dump_id = ?1 and t.locks_waiting like ?2",
            nativeQuery = true)
List<ThreadDo> findAllByDumpDoAndLocksWaitingContains(Long dumpId, String lockWaiting);