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我在MySQL中的观点是它不起作用

create-view mysql5

0

ParisNakitaKejser · 技术社区 · 16 年前

SELECT
    *

FROM
    view_shop_invoicer_list

WHERE
    accept_date >= '2009-10-16 00:00:00' AND
    accept_date <= '2009-10-31 23:59:59' AND
    shopid = [SHOPID];

我的视图如下所示,它不会将我的accept_日期带入该视图,我是否从SELECTE复制/粘贴它并将int插入我的视图?它会起作用,但不是顺序方式:(

DROP VIEW IF EXISTS view_shop_invoicer_list;
CREATE VIEW view_shop_invoicer_list AS

SELECT
    SUM( it.transamount ) AS beloeb,
    SUM( it.cargo_fee ) AS cargo,
    SUM( 
        ( 
            it.transamount - 
            ( 
                ( it.transamount - it.cargo_fee ) / 100 * 
                ( ms.pay_adm_fee + ms.pay_marks_fee + ms.pay_kick_fee ) - 
                ( it.adm_fee + it.marketing_fee + it.kickback_fee )
            ) 
        ) 
    ) AS shop_payout,
    SUM( fc_return_fee( it.transamount , it.cargo_fee , ms.pay_adm_fee , it.adm_fee ) ) AS shop_adm_fee,
    SUM( fc_return_fee( it.transamount , it.cargo_fee , ms.pay_marks_fee , it.marketing_fee ) ) AS shop_marks_fee,
    SUM( fc_return_fee( it.transamount , it.cargo_fee , ms.pay_kick_fee , it.kickback_fee ) ) AS shop_kick_fee,
    it.shopid AS shopid,
    it.accept_date AS accept_date

FROM
    invoice_trans it INNER JOIN invoice i ON it.orderid = i.ordreid
    INNER JOIN shops ms ON ms.id = it.shopid

WHERE
    i.status != 0

表1:发票交易

CREATE TABLE `invoice_trans` (
  `id` int(11) NOT NULL auto_increment,
  `orderid` varchar(32) NOT NULL default '0',
  `transamount` int(11) NOT NULL default '0',
  `transact` varchar(32) NOT NULL default '',
  `transnr` int(11) NOT NULL default '0',
  `shopid` int(11) NOT NULL default '0',
  `status` int(11) NOT NULL default '0',
  `accept_date` timestamp NOT NULL default '0000-00-00 00:00:00',
  `md5_key_declie` varchar(32) NOT NULL,
  `declie_date` datetime NOT NULL default '0000-00-00 00:00:00',
  `pay_points` int(1) NOT NULL default '0',
  `cargo_fee` int(11) NOT NULL default '4900',
  `first_time_discount` int(2) NOT NULL default '0',
  `adm_fee` int(11) NOT NULL default '0',
  `marketing_fee` int(11) NOT NULL default '0',
  `kickback_fee` int(11) NOT NULL default '0',
  PRIMARY KEY  (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1

CREATE TABLE `invoice` (
  `id` int(11) NOT NULL auto_increment,
  `userid` int(11) NOT NULL default '0',
  `per_fullname` varchar(64) NOT NULL,
  `per_street` varchar(64) NOT NULL,
  `per_zipcode` int(4) NOT NULL,
  `per_city` varchar(64) NOT NULL,
  `per_email` varchar(256) NOT NULL default '',
  `fak_fullname` varchar(64) NOT NULL default '',
  `fak_street` varchar(64) NOT NULL,
  `fak_zipcode` int(4) NOT NULL,
  `fak_city` varchar(64) NOT NULL,
  `fak_email` varchar(256) NOT NULL default '',
  `push_date` datetime NOT NULL default '0000-00-00 00:00:00',
  `status` int(1) NOT NULL default '0',
  `splits` int(11) NOT NULL default '0',
  `dibs_ordreid` varchar(32) NOT NULL default '0',
  `reftag` varchar(64) NOT NULL,
  `vonchers_prices` int(11) NOT NULL default '0',
  `ordre_complate` int(1) NOT NULL default '0',
  PRIMARY KEY  (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1

2 回复 | 直到 16 年前

1

0

Kris 16 年前

没有 ordreid (或 orderid invoice fc_return_fee 或者测试数据,所以可测试性非常有限。

mysql给你的错误消息是什么?

2

0

ParisNakitaKejser 16 年前

我发现了问题。。。。我这样解决问题。

DROP VIEW IF EXISTS view_shop_invoicer_list;
CREATE VIEW view_shop_invoicer_list AS

SELECT
    it.transamount AS beloeb,
    SUM( it.cargo_fee ) AS cargo,
    ( 
            it.transamount - 
            ( 
                ( it.transamount - it.cargo_fee ) / 100 * 
                ( ms.pay_adm_fee + ms.pay_marks_fee + ms.pay_kick_fee ) - 
                ( it.adm_fee + it.marketing_fee + it.kickback_fee )
            ) 
    ) AS shop_payout,
    fc_return_fee( it.transamount , it.cargo_fee , ms.pay_adm_fee , it.adm_fee ) AS shop_adm_fee,
    fc_return_fee( it.transamount , it.cargo_fee , ms.pay_marks_fee , it.marketing_fee ) AS shop_marks_fee,
    fc_return_fee( it.transamount , it.cargo_fee , ms.pay_kick_fee , it.kickback_fee ) AS shop_kick_fee,
    it.shopid AS shopid,
    it.accept_date AS accept_date

FROM
    invoice_trans it INNER JOIN invoice i ON it.orderid = i.ordreid

WHERE
    i.status != 0

GROUP BY
    it.id;

我使用这个选择;)坦克求救,伙计们。

SELECT
                    SUM( beloeb ) AS beloeb,
                    SUM( cargo ) AS cargo,
                    SUM( shop_payout ) AS shop_payout,
                    SUM( shop_adm_fee ) AS shop_adm_fee,
                    SUM( shop_marks_fee ) AS shop_marks_fee,
                    SUM( shop_kick_fee ) AS shop_kick_fee,
                    accept_date,
                    shopid

                FROM
                    view_shop_invoicer_list

                WHERE
                    accept_date >= '". $this->from_date ."' AND
                    accept_date <= '". $this->to_date ."'

                GROUP BY
                    shopid