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如何在Oracle过程中将选择结果存储到变量中

select-into stored-procedures oracle

10

MichaÅ Ziober · 技术社区 · 16 年前

我写了一个简单的程序。我尝试将选择结果存储在变量中。我使用“SELECT INTO”查询,但我不能这样做。

例子:

DECLARE
     v_employeeRecord  employee%ROWTYPE;
BEGIN
 SELECT * INTO v_employeeRecord
      FROM Employee WHERE Salary > 10;
END;

2 回复 | 直到 16 年前

1

14

Adam Paynter 16 年前

DECLARE
     CURSOR v_employeeRecords IS
          SELECT * FROM Employee WHERE Salary > 10;
     v_employeeRecord  employee%ROWTYPE;
BEGIN
     FOR v_employeeRecord IN v_employeeRecords LOOP
          /* Do something with v_employeeRecord */
     END LOOP;
END;

或者,您可以创建一个 TABLE 变量:

DECLARE
     v_employeeRecord  employee%ROWTYPE;
     v_employeeRecords IS TABLE OF employee%ROWTYPE;
     i BINARY_INTEGER;
BEGIN
 SELECT * BULK COLLECT INTO v_employeeRecords
      FROM Employee WHERE Salary > 10;

 i := v_employeeRecords.FIRST;
 WHILE v_employeeRecords.EXISTS(i) LOOP
     v_employeeRecord := v_employeeRecords(i);
     /* Do something with v_employeeRecord */
     i := v_employeeRecords.NEXT(i);
 END;
END;

2

8

Community Mohan Dere 9 年前

您需要构建一个循环来浏览结果集:

Adam

BEGIN
   FOR c_emp IN (SELECT * 
                   FROM Employee 
                  WHERE Salary > 10) LOOP
      /* do something with each row, for example:*/
      UPDATE foo SET bar = bar + c_emp.salary WHERE id = c_emp.id;
   END LOOP;
END;