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在SOAP请求中,XML元素被包装在额外的标记中

c#-4.0 soap wcf .net c#

Yngve B-Nilsen · 技术社区 · 14 年前

嗨,我有一个服务代理,有一个方法:

void SendRequest(MyMessage msg);

mymessage定义如下:

[MessageContract(IsWrapped=false)]
public class MyMessage{
    [MessageBodyMember(Order=0)]
    public XmlElement Body;

    public MyMessage(XmlElement Body){
        this.Body = Body;
    }
}

现在,问题是当我发送请求时,主体被这样一个标签包裹:

<s:Body>
    <Body>
         <MyMessage>
               <SomeData>Hello world</SomeData>
         </MyMessage>
    </Body>
</s:Body>

当我真正想要的是:

<s:Body>
    <MyMessage>
               <SomeData>Hello world</SomeData>
    </MyMessage>
</s:Body>

有人能帮忙吗?我开始绝望了!:

编辑:我想发送xmlement的原因是服务将接受各种XML格式,并在服务器端进行XSD验证和转换。这只是一种包装。

我也不可能让端点服务器简单地接受“错误的”XML结构,因为我无法控制它。

1 回复 | 直到 14 年前

Yngve B-Nilsen 14 年前

好吧,看来我得完全放弃WCF才行。

我所做的是创建两个简单的方法:

    XDocument ConstructSoapEnvelope(string messageId, string action, XDocument body)
    {
        XDocument xd = new XDocument();
        XNamespace s = "http://schemas.xmlsoap.org/soap/envelope/";
        XNamespace a = "http://www.w3.org/2005/08/addressing";

        XElement soapEnvelope = new XElement(s + "Envelope", new XAttribute(XNamespace.Xmlns + "s", s), new XAttribute(XNamespace.Xmlns + "a", a));
        XElement header = new XElement(s + "Header");
        XElement xmsgId = new XElement(a + "MessageID", "uuid:" + messageId);
        XElement xaction = new XElement(a + "Action", action);
        header.Add(xmsgId);
        header.Add(xaction);

        XElement soapBody = new XElement(s + "Body", body.Root);
        soapEnvelope.Add(header);
        soapEnvelope.Add(soapBody);
        xd = new XDocument(soapEnvelope);
        return xd;
    }

    string HttpSOAPRequest(XmlDocument doc, string add, string proxy, X509Certificate2Collection certs)
    {
        HttpWebRequest req = (HttpWebRequest)WebRequest.Create(add);
        req.ClientCertificates = certs;
        if (proxy != null) req.Proxy = new WebProxy("", true);

        req.Headers.Add("SOAPAction", "\"\"");

        req.ContentType = "text/xml;charset=\"utf-8\"";
        req.Accept = "text/xml";
        req.Method = "POST";
        Stream stm = req.GetRequestStream();
        doc.Save(stm);
        stm.Close();
        WebResponse resp = req.GetResponse();
        stm = resp.GetResponseStream();
        StreamReader r = new StreamReader(stm);

       return r.ReadToEnd();
    }