我的foreach循环无法将数据插入数据库。如果我将insert语句从循环中去掉,它可以正常工作,但只适用于1个项。回声也没有返回任何数据。如果有人能检查我的代码并指出我的错误,我将不胜感激。
假设所有连接都已建立,并且al$u post值正确。多谢
<?php
session_start();
include($_SERVER['DOCUMENT_ROOT'] . '/lsorg/users/Connections/ls.php');
$company = strtoupper(mysqli_real_escape_string($conn, $_SESSION['ls_idcode_usr']));
$activity = "Box Return";
$address = ucwords(mysqli_real_escape_string($conn, $_POST['address']));
$service = ucwords(mysqli_real_escape_string($conn, $_POST['service']));
$success = 'SUCCESS';
$authorised = mysqli_real_escape_string($conn, $_SESSION['ls_name_usr']);
$dept = strtoupper(mysqli_real_escape_string($conn, $_POST['dept']));
$boxitems = $_POST['sub'];
$box = implode(",",$boxitems);
$array = array();
$array = $boxitems;
foreach ($array as $boxes) {
$outString .= "$box" . " ";
//$boxitem = $box;
$sql = "INSERT INTO act
(service, activity, department,
company, address, user,
`date`, item, new)
VALUES ('".$service."', '".$activity."', '".$dept."',
'".$company."', '".$address."', '".$authorised."',
NOW(), '".$boxes."', '1')";
$result = mysqli_query($conn, $sql) or die ('Error inserting box:' . mysqli_error());
}
echo $outString;
mysqli_close($conn); // Connection Closed
?>
添加调试代码后
警告:implode()[函数.implode]:在第16行的c:\wamp\www\lsorg\users\brtn.php中传递的参数无效警告:在第22行的c:\wamp\www\lsorg\users\brtn.php中为foreach()提供的参数无效字符串(10)“demobox050”注意:未定义的变量:在第39行的c:\wamp\www\lsorg\users\brtn.php中的outstring
答复中的内容
$_POST['sub']
DEMOBOX044,DEMOBOX050