单击打开C中托盘图标的菜单#

这应该为您做到:

private void notifyIcon1_Click(object sender, EventArgs e)
        {
            contextMenuStrip1.Show(Cursor.Position.X, Cursor.Position.Y);
        }

另一种我发现效果更好的方法是:

private void notifyIcon1_MouseUp(object sender, MouseEventArgs e)
    {
        if (e.Button == MouseButtons.Left)
        {
            System.Reflection.MethodInfo mi = typeof(NotifyIcon).GetMethod("ShowContextMenu", System.Reflection.BindingFlags.Instance | System.Reflection.BindingFlags.NonPublic);
            mi.Invoke(notifyIcon1, null);
        }
    }