在Bash数组中添加元素以稍后打印它们

我正在数组中添加元素( Add a new element to an array without specifying the index in Bash )但我得到了一个意想不到的结果。我想在数组中添加元素和/或迭代数组以打印其值时,我做错了什么。

代码:

for name in $(cat list.txt); do
    host $name.$DOMAIN | grep "has address" | cut -d" " -f4
done

for name in $(cat list.txt); do
    echo "."
    IPS+=(`host $name.$DOMAIN | grep "has address" | cut -d" " -f4`)
    echo ${#IPS[@]}
done

for ip in $IPS; do
    echo "IP: $ip"
done

输出:

12.210.145.45
67.20.71.219
75.58.197.10
31.70.88.22
.
1
.
3
.
4
.
4
.
4
IP: 12.210.145.45

预期产量:

输出:

12.210.145.45
67.20.71.219
75.58.197.10
31.70.88.22
.
1
.
2
.
3
.
4
IP: 12.210.145.45
IP: 67.20.71.219
IP: 75.58.197.10
IP: 31.70.88.22