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如何用C语言从ListView中编写XML文件#

linq-to-xml file-io listview xml c#

Thorin Oakenshield · 技术社区 · 14 年前

我有一个 ListView 像控制一样

alt text

所以xml文件将如下所示

<root>
 <Child Name ="A1" val1="1" val2="0"/>
 <Child Name ="A2" val1="1" val2="2"/>
 <Child Name ="A3" val1="1" val2="3"/>
 <Child Name ="A4" val1="1" val2="4"/>
 <Child Name ="A5" val1="1" val2="5"/>
 <Child Name ="A6" val1="6" val2="0"/>
 <Child Name ="A7" val1="7" val2="0"/>
</root>

如果数据存储在 List 或 Dictionary ,然后我知道要使用XML来实现这一点

但是如何从列表视图中执行此操作

XDocument XD=new XDocument(new XElement("root",........// what i have to do here.......

请帮我。。。

2 回复 | 直到 14 年前

Frédéric Hamidi 13 年前

可以查询列表视图子项及其列标题:

XDocument document = new XDocument(new XElement("root",
    from item in yourListView.Items.Cast<ListViewItem>()
    select new XElement("Child",
        item.SubItems.Cast<ListViewSubItem>()
            .Select((subitem, i) => new XAttribute(
                i == 0 ? "Name" : yourListView.Columns[i].Text.ToLower(),
                subItem.Text)))));

编辑: 因为两者都不是 ListViewItemCollection ListViewSubItemCollection 支持开箱即用的查询运算符,我们需要调用 Cast<T>()

gonzobrains Etienne Lawlor 12 年前

这里有一个简单的例子。这里的目标是使用XmlTextWriter完成它。当然,需要修改此示例以满足特定的文件I/O和XML格式设置需要:

public static bool ExportListViewlToXML(ListView listview, String filePath, String fileName)
    {
        FileStream fileStream;
        StreamWriter streamWriter;
        XmlTextWriter xmlTextWriter;

        try
        {
            // overwrite even if it already exists
            fileStream = new FileStream(fileName, FileMode.Create, FileAccess.Write, FileShare.None);

            streamWriter = new StreamWriter(fileStream);
            xmlTextWriter = new XmlTextWriter(streamWriter);
            xmlTextWriter.Formatting = Formatting.Indented;
            xmlTextWriter.WriteStartDocument();
            xmlTextWriter.WriteStartElement("Items");

            const int SUBITEM1_POS = 0;
            const int SUBITEM2_POS = 1;
            const int SUBITEM3_POS = 2;

            for (int i = 0; i < listview.Items.Count; i++)
            {
                String currentSubItem1 = listview.Items[i].SubItems[SUBITEM1_POS].Text;
                String currentSubItem2 = listview.Items[i].SubItems[SUBITEM2_POS].Text;
                String currentSubItem3 = listview.Items[i].SubItems[SUBITEM3_POS].Text;

                xmlTextWriter.WriteStartElement("Item");
                xmlTextWriter.WriteAttributeString("subitem1", currentSubItem1.ToString());
                xmlTextWriter.WriteAttributeString("subitem2", currentSubItem2.ToString());
                xmlTextWriter.WriteAttributeString("subitem3", currentSubItem3.ToString());
                xmlTextWriter.WriteEndElement();
            }

            xmlTextWriter.WriteEndDocument();
            xmlTextWriter.Flush();
            xmlTextWriter.Close();

            return true;
        }
        catch (IOException ex)
        {
            // do something about your error
            return false;
        }
    }