我开始了解boost::variant。我认为这个例子是可行的。
#include <boost/fusion/sequence.hpp>
#include <boost/fusion/include/sequence.hpp>
#include <boost/variant/variant.hpp>
#include <string>
#include <vector>
#include <iostream>
#include <boost/variant/get.hpp>
boost::variant< bool,long,double,std::string,
std::vector<boost::variant<bool> > > v4;
void main()
{
std::vector<boost::variant<bool> > av (1);
v4= av;
try
{
bool b=
boost::get<bool> (v4[0]); // <--- this is line 20
std::cout << b;
}
catch (boost::bad_get v)
{
std::cout << "bad get" <<std::endl;
}
}
我得到一个编译错误:
d:\m\upp\boosttest\main.cpp(20):错误C2676:二进制“[”:“boost::variant”do
不定义此运算符或转换为预定义运算符可接受的类型
具有
[
BoOL,
T1=长,
T2=双,
T3=STD::
t4=标准::矢量>
]
