使用xpath和xsl遍历xml文档

我使用XSL和XPATH遍历、读取和转换一个复杂的XML文件,其中有多个名称相同但值不同的节点。下面是我的示例xml文件-

    <core>
   <address>
      <postalZipCode>90017</postalZipCode>
      <updateSource>xxxxxx</updateSource>
      <city>LOS ANGELES</city>
      <stateProvince>CA</stateProvince>
      <type>MAILING</type>
      <line1>818 WEST SEVENTH STREET</line1>
   </address>
   <address>
      <postalZipCode>95014</postalZipCode>
      <updateSource>xxxxxx</updateSource>
      <city>CUPERTINO</city>
      <stateProvince>CA</stateProvince>
      <type>PRIMARY</type>
      <line1>1234 XYZ STREET</line1>
   </address>
    <memberId>0</memberId>
 </core>

    <xsl:template match="core">       
    <xsl:if test="memberId['0'] and address/type['MAILING']">
    <fo:table-row>
        <fo:table-cell><fo:block /></fo:table-cell>                     
        <fo:table-cell xsl:use-attribute-sets="data">
            <fo:block>Line 1</fo:block>
        </fo:table-cell>
        <fo:table-cell xsl:use-attribute-sets="data">
            <fo:block><xsl:value-of select="address/line1/text()"/>
        </fo:block>
        </fo:table-cell>                                              
    </fo:table-row>

这里的专家能否建议,是否有其他方法可以强制XSL读取地址所在位置的正确值,而不是读取它找到的第一个值???