如何在SQL Server Compact Edition Select语句中复制rank函数?

SELECT x.[Product Name], x.[Unit Price], COUNT(y.[Unit Price]) Rank 
FROM Products x, Products y 
WHERE x.[Unit Price] < y.[Unit Price] or (x.[Unit Price]=y.[Unit Price] and x.[Product Name] = y.[Product Name]) 
GROUP BY x.[Product Name], x.[Unit Price] 
ORDER BY x.[Unit Price] DESC, x.[Product Name] DESC;

解决方案修改自 查找学生的排名-SQL Compact 在 Finding rank of the student -Sql Compact

用途:

  SELECT x.[Product Name], x.[Unit Price], COUNT(y.[Unit Price]) AS Rank 
    FROM Products x
    JOIN Products y ON x.[Unit Price] < y.[Unit Price] 
                  OR (    x.[Unit Price]=y.[Unit Price] 
                      AND x.[Product Name] = y.[Product Name]) 
GROUP BY x.[Product Name], x.[Unit Price] 
ORDER BY x.[Unit Price] DESC, x.[Product Name] DESC;

先前:

SELECT y.id,
       (SELECT COUNT(*)
         FROM TABLE x
        WHERE x.id <= y.id) AS rank
  FROM TABLE y