删除双单引号,但不删除单引号

试试这个正则表达式:

\B'((?:(?!'\B)[\s\S])*)'

将每个匹配项替换为 \1

Click for Demo

代码( Result

re = /\B'((?:(?!'\B)[\s\S])*)'/m
str = 'That\'s \'large\'
The 69\'ers\' drummer won\'t like this.
He said, \'it\'s clear this does not work\'. It does not fit the \'contractual obligations\''
subst = '\\1'

result = str.gsub(re, subst)

# Print the result of the substitution
puts result

说明:

• \B
• ((?:(?!'\B)[\s\S])*) -匹配0+个出现的任何字符 [\s\S] 哪个(不以开头) ' 后跟非单词边界)。这是在第1组中捕获的。
• -匹配a

这是一个像解析XML或HTML这样的泥潭,不能用regex来完成,但是你可以假装它基本上可以工作。你可以调整它永远不会得到正确的。

你可以寻找平衡的引号,也就是成对的引号,但这没有帮助。是 That's 'large' 被剥离为 Thats large' 或 That's large

相反,你需要给它一个英语语法的理解,当 ' apostrophe 对一个报价。一些简单的东西,知道收缩和所有格的基本知识。收缩: don't won't I'll . 所有格: Joe's s' . 也许你可以敲一个正则表达式跳过这些。

但很快就会变得复杂起来。 KO'd fo'c's'le . 或者某人的名字 O'Doole .

可以 It's clear he said, 'this isn't a contraction'. 匹配前面的报价 this contraction 可能是安全的。

# Use negative look behind and ahead to look for quotes which are
# not after and before a word character.
# Use a non-greedy match to catch multiple pairs of quotes.
re = /(?<!\w)'(.*?)'(?!\w)/
sentence.gsub(re, '\1')

这在很多情况下都有效。

That's 'large' -> That's large
Eat at Joe's -> Eat at Joe's
I'll be Jane's -> I'll be Jane's
Jones' three cats' toys. -> Jones' three cats' toys.
It's clear he said, 'this isn't a contraction'. -> It's clear he said, this isn't a contraction.
'scare quotes' -> scare quotes
The 69'ers' drummer -> The 69'ers' drummer
Was She's success greater, or King Solomon's Mines's? -> Was She's success greater, or King Solomon's Mines's?
The 69'er's drummer and their 'contractual obligations'. -> The 69'er's drummer and their contractual obligations.
He said, 'it's clear this doesn't work'. -> He said, it's clear this doesn't work.

但不总是这样。

His 'n' Hers's first track is called 'Joyriders'. -> His n Hers's first track is called Joyriders.

如果单引号仅出现在单词字符(即A-z、A-z、0-9或下划线字符)周围,则会有轻微的变化。您可以使用:

phrase = "That's 'large' and not 'small', but it's still 'amazing'."
phrase.gsub(/'(\w*)'/, '\1')
=> "That's large and not small, but it's still amazing."