C regex提取标签

当然:

Regex.Matches(myString, "<([^>]+)>");

PowerShell示例:

PS> $s = @'
>> Hi my name is <Name>
>> Hi <name>, shall we go for a <Drink>
>> '@
>>
PS> [regex]::Matches($s,  '<([^>]+)>') | ft

Groups                Success Captures      Index      Length Value
------                ------- --------      -----      ------ -----
{<Name>, Name}           True {<Name>}         14           6 <Name>
{<name>, name}           True {<name>}         25           6 <name>
{<Drink>, Drink}         True {<Drink>}        51           7 <Drink>

"</?[a-z][a-z0-9]*[^<>]*>"

要使用它,请尝试如下操作:

try
{
    Regex regexObj = new Regex("</?[a-z][a-z0-9]*[^<>]*>", RegexOptions.IgnoreCase);
    Match matchResults = regexObj.Match(subjectString);
    while (matchResults.Success)
    {
        // Do Stuff

        // matched text: matchResults.Value
        // match start: matchResults.Index
        // match length: matchResults.Length
        matchResults = matchResults.NextMatch();
    } 
}
catch (ArgumentException ex)
{
    // Syntax error in the regular expression
}

为什么不做一些更简单的事情,比如使用c s字符串。替换?您传入要替换的字符串,并给它任何要替换的值。

请参见此处获取示例: http://msdn.microsoft.com/en-us/library/fk49wtc1.aspx