我有一个带有基类(消息)的程序,许多其他类都是从中派生的(特别是文章和注释)。我想创建一个条件来选择RootMessage属性类型为Article的所有注释(我有一些其他类型的潜在RootMessages)。但我似乎找不到如何在标准中添加这种约束。
public virtual ICollection<Comment> GetCommentsByArticle(ISession session)
{
var c = session.CreateCriteria(typeof(Comment))
.Add(Expression.Eq("Author", this))
.AddOrder(Order.Desc("CreationDate"))
.SetMaxResults(20);
var commentList = c.List<Comment>();
return commentList;
}
但这当然会返回作者的每一条评论。我想要的是这个作者的每个评论都有一个文章类型的根消息。
这些是映射。
<?xml version="1.0" encoding="utf-8" ?>
<hibernate-mapping xmlns="urn:nhibernate-mapping-2.2"
assembly="FolkeLib"
namespace="Folke.Code.Domain">
<class name="Message" discriminator-value="0">
<id name="Id">
<generator class="native"></generator>
</id>
<discriminator column="MessageType" type="Int32"/>
<timestamp column="ModificationDate" name="ModificationDate"/>
<property name="CreationDate" index="ArticleCreationDate"/>
<many-to-one name="Author"/>
<property name="Text" type="StringClob">
<column name="Text" sql-type="text"/>
</property>
<property name="Locked"/>
<many-to-one name="Locker" not-null="false"/>
<many-to-one name="RootMessage" not-null="false"/>
<many-to-one name="ParentMessage" not-null="false"/>
<property name="Score"/>
<many-to-one name="Site" not-null="true"/>
条款:
<?xml version="1.0" encoding="utf-8" ?>
<hibernate-mapping xmlns="urn:nhibernate-mapping-2.2"
assembly="FolkeLib"
namespace="Folke.Code.Domain">
<subclass name="Article" extends="Message" discriminator-value="1">
<property name="Title"/>
<set name="TagSet" lazy="true" table="MessageTag">
<key column="MessageId"/>
<many-to-many class="Tag" column="TagId"/>
</set>
<set name="ImageSet" lazy="true" table="MessageImage">
<key column="MessageId"/>
<many-to-many class="Image" column="ImageId"/>
</set>
<many-to-one name="Forum"/>
</subclass>
</hibernate-mapping>
<?xml version="1.0" encoding="utf-8" ?>
<hibernate-mapping xmlns="urn:nhibernate-mapping-2.2"
assembly="FolkeLib"
namespace="Folke.Code.Domain">
<subclass name="Comment" extends="Message" discriminator-value="2">
</subclass>
</hibernate-mapping>
感谢任何帮助!
