通过多对多关系的属性访问的最佳方式是什么?

假设你知道玩家的id( player_id )以及特定游戏的id( game_id ),您可以执行以下操作:

Show.where('player_id = ? and game_id = ?', player_id, game_id).first.update_attributes(:going => true)

这更为冗长,但也有可能:

player = Player.find(player_id)
show = player.shows.find_by_game_id(game_id)
show.update_attributes(:going => true)

如果你想迭代游戏,你可以做到:

player = Player.find(id_of_player)

player.shows.each do |show|
  if show.game == ... # condition that decides whether player's going or not
    show.update_attributes(:going => true) 
  end
end