动态生成的Mocha测试不在异步/等待上下文中执行

getStatus()

)你可以玩它 here on repl.it ):

const sleep = require('util').promisify(setTimeout);

const getStatus = async function() {
    await sleep(1000);
    return 2;
};

describe('main describe', async function () {
    let uids = [1,2,3];

    describe('Tha test!', async function () {
        console.info('started describe() block...');

        let outcome;
        let status;

        const callback = function () {
            console.info(`inside callback, status is ${status} and outcome is ${outcome}`);
            expect(status).to.equal(outcome);
        };

        for(let uid in uids) {
            status = await getStatus(uids[uid]);
            console.info('the status returned by getStatus is:', status);
            it(`The status for ${uids[uid]} should be ${outcome}`, callback);
        }
    });
});

注意:it()子句中的回调是受 this question .

started describe() block...

  0 passing (0ms)

the status returned by getStatus is: 2
the status returned by getStatus is: 2
the status returned by getStatus is: 2

预期产出:

started describe() block...

the status returned by getStatus is: 2
the status returned by getStatus is: 2
the status returned by getStatus is: 2

      1) number 0 should equal 2
      2) number 1 should equal 2
      ✓ number 2 should equal 2

  1 passing (11ms)
  2 failing

it() 不执行的条款?