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生成通配符子目录目标

subdirectory target wildcard makefile

Zed · 技术社区 · 16 年前

我想做如下的事情,但显然不起作用。请注意,我还有清洁、测试等目标,所以%可能根本不是一个好主意。

LIBS=lib/*

all: $(LIBS)

%:
  (cd $@; $(MAKE))

感谢您的帮助!

3 回复 | 直到 16 年前

mrkj 16 年前

以下内容将与GNU一起使用 make :

LIBS=$(wildcard lib/*)
all: $(LIBS)
.PHONY: force
$(LIBS): force
  cd $@ && pwd

如果在中可能存在目录以外的内容 lib ,你也可以使用:

LIBS=$(shell find lib -type d)

要解决多目标问题,可以为每个目录构建特殊目标,然后去掉子构建的前缀:

LIBS=$(wildcard lib/*)
clean_LIBS=$(addprefix clean_,$(LIBS))
all: $(LIBS)
clean: $(clean_LIBS)
.PHONY: force
$(LIBS): force
  echo make -C $@
$(clean_LIBS): force
  echo make -C $(patsubst clean_%,%,$@) clean

Greg 13 年前

还有一种方法可以只使用gmake命令列出子目录,而不使用任何shell命令:

test:
  @echo $(filter %/, $(wildcard lib/*/))

'/' . 要删除它,可以使用替换图案:

subdirs = $(filter %/, $(wildcard lib/*/))
test:
  @echo $(subdirs:%/=%)

FULL_DIRS =$(filter %/, $(wildcard lib/*/))
LIB_DIRS  =$(FULL_DIRS:%/=%)
DIRS_CMD  =$(foreach subdir, $(LIB_DIRS), make-rule/$(subdir))

make-rule/%:
  cd $* && $(MAKE)

all: DIRS_CMD

基本上,目标 'all' 列出所有子目录作为先决条件。例如,如果 LIB_DIRS lib/folder1 lib/folder2 然后扩展将如下所示:

all: make-rule/lib/folder1 make-rule/lib/folder2

“全部” 'make-rule/%:' '$*' 提取后面的字符串 'make-rule/' 并将其用作配方中的参数。例如,第一个先决条件将如下匹配和扩展:

make-rule/lib/folder1:
  cd lib/folder1 && $(MAKE)

klsdjfhsalkjfhl 10 年前

如果您想调用不同的目标,而不是未知数量的子目录中的所有目标,该怎么办?

以下Makefile使用宏,因此为多个子目录创建一个转发虚拟目标,以将命令行中的给定目标应用于每个子目录:

# all direct directories of this dir. uses "-printf" to get rid of the "./"
DIRS=$(shell find . -maxdepth 1 -mindepth 1 -type d -not -name ".*" -printf '%P\n')
# "all" target is there by default, same logic as via the macro
all: $(DIRS)

$(DIRS):
    $(MAKE) -C $@
.PHONY: $(DIRS)

# if explcit targets where given: use them in the macro down below. each target will be delivered to each subdirectory contained in $(DIRS).
EXTRA_TARGETS=$(MAKECMDGOALS)

define RECURSIVE_MAKE_WITH_TARGET
# create new variable, with the name of the target as prefix. it holds all
# subdirectories with the target as suffix
$(1)_DIRS=$$(addprefix $(1)_,$$(DIRS))

# create new target with the variable holding all the subdirectories+suffix as
# prerequisite
$(1): $$($1_DIRS)

# use list to create target to fullfill prerequisite. the rule is to call
# recursive make into the subdir with the target
$$($(1)_DIRS):
      $$(MAKE) -C $$(patsubst $(1)_%,%,$$@) $(1)

# and make all targets .PHONY
.PHONY: $$($(1)_DIRS)
endef

# evaluate the macro for all given list of targets
$(foreach t,$(EXTRA_TARGETS),$(eval $(call RECURSIVE_MAKE_WITH_TARGET,$(t))))

希望这有帮助。在处理并行性时非常有用:make-j12使用具有这些目标的makefile清除树中的所有内容。。。和往常一样:玩make是危险的,不同的元编程层次太接近了,-)