emacs lisp-mapcar不将函数应用于所有元素?

我有一个函数,它接受一个列表并替换一些元素。我把它构造为一个闭包,这样自由变量就不能在函数之外被修改。

(defun transform (elems)
  (lexical-let ( (elems elems) )
    (lambda (seq)
      (let (e)
    (while (setq e (car elems))
      (setf (nth e seq) e)
      (setq elems (cdr elems)))
    seq))))

我把这个叫做清单。

(defun tester (seq-list)
  (let ( (elems '(1 3 5)) )
    (mapcar (transform elems) seq-list)))

(tester (list (reverse (number-sequence 1 10)) 
          '("a" "b" "c" "d" "e" "f")))
=> ((10 1 8 3 6 5 4 3 2 1) ("a" "b" "c" "d" "e" "f"))

它似乎没有将该函数应用于提供给测试人员()的列表的第二个元素。但是,如果我显式地将这个函数应用于单个元素,它会工作…

(defun tester (seq-list)
  (let ( (elems '(1 3 5)) )
    (list (funcall (transform elems) (car seq-list))
          (funcall (transform elems) (cadr seq-list)))))

(tester (list (reverse (number-sequence 1 10)) 
          '("a" "b" "c" "d" "e" "f")))
=> ((10 1 8 3 6 5 4 3 2 1) ("a" 1 "c" 3 "e" 5))

如果我用和上面相同的概念编写一个简单的函数,mapcar似乎可以工作…我可能做错什么了?

(defun transform (x)
  (lexical-let ( (x x) )
    (lambda (y) 
      (+ x y))))

(defun tester (seq)
  (let ( (x 1) )
    (mapcar (transform x) seq)))

(tester (list 1 3))    
=> (2 4)

谢谢