亲缘关系

我有两个简单的模型。首先,一个称为Builds(mysql),第二个称为SlotOptions(mongodb)。每个构建可以有5个分配的插槽。基于 https://stackoverflow.com/a/55132863/2513428

select * from `builds` where `builds`.`id` = 37 limit 1
SlotOptions.find({"heroName":{"$in":[37]}},{"typeMap":{"root":"array","document":"array"}})

桌子。 内置插槽选项 (mysql)

+----------------+--------+----------------------------------------+
|      Name      |  Type  |                  Desc                  |
+----------------+--------+----------------------------------------+
| slot_option_id | char50 | // FK, Name of slot option f.e "Hero1" |
| build_id       | int    | // FK, Build id                        |
| pos            | int    | // Number 1-5                          |
+----------------+--------+----------------------------------------+

例子 :

+----------------+----------+-----+
| slot_option_id | build_id | pos |
+----------------+----------+-----+
| Hero1          |       37 |   1 |
| Hero2          |       37 |   2 |
| Hero3          |       37 |   3 |
| Hero4          |       37 |   4 |
| Hero5          |       37 |   5 |
+----------------+----------+-----+

桌子。 (mysql)

+------+------+------------------------+
| Name | Type |          Desc          |
+------+------+------------------------+
| id   | int  | // PK, of Builds Table |
| ...  | ...  | // and other columns   |
+------+------+------------------------+

这是build类和用法示例。

 class BuildDB extends Model
{
    use HybridRelations;
    protected $connection = 'mysql';
    public function slots()
    {
        return $this->belongsToMany(
            SlotOptions::class, 'build_slot_option', 'build_id', 'slot_option_id'
        );
    }
}

BuildDB::with('slots')->find(5);

当涉及到第二个查询时,它应该 不插入生成id 那里 {"$in":[37]} 所有的插槽名称,从tb 插槽选项 列。例如 {"$in":['Hero1','Hero2']}