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如何在bash中只打印gpg密钥的主uid?

gnupg bash

1

Wang · 技术社区 · 5 年前

我有指纹。我知道我能行 gpg -k <finger print>

0 回复 | 直到 5 年前

1

larsks 5 年前

我相信你在找 --with-colons 选项,它为脚本解析提供稳定的输出。给这样一把钥匙:

pub   rsa2048/0x362D63A80853D4CF 2013-06-21 [SC]
      3E70A502BB5255B6BB8E86BE362D63A80853D4CF
uid                   [ultimate] Lars LastName <lars@...>
uid                   [ultimate] keybase.io/larsks <larsks@...>
sub   rsa2048/0x042DF6CF74E4B84C 2013-06-21 [S] [expires: 2023-07-01]
sub   rsa2048/0x426D9382DFD6A7A9 2013-06-21 [E]
sub   rsa2048/0xEE1A8B9F9369CC85 2013-06-21 [A]

--用冒号 输出如下所示:

tru::1:1615472480:1656257313:3:1:5
pub:u:2048:1:362D63A80853D4CF:1371778249:::u:::scESCA::::::23::0:
fpr:::::::::3E70A502BB5255B6BB8E86BE362D63A80853D4CF:
uid:u::::1416450403::C2B1F8BE099BCF889677DBC639C4427C04BC230A::Lars LastName <lars@...>::::::::::0:
uid:u::::1407979245::E8B853E07D5D3F9BAD96435FA508017A644467AE::keybase.io/larsks <larsks@...>::::::::::0:
sub:u:2048:1:042DF6CF74E4B84C:1371778249:1688234376:::::s::::::23:
fpr:::::::::FDE8364F7FEA3848EF7AD3A6042DF6CF74E4B84C:
sub:u:2048:1:426D9382DFD6A7A9:1371778250::::::e::::::23:
fpr:::::::::01A14A356BFE207E7CF6EAFE426D9382DFD6A7A9:
sub:u:2048:1:EE1A8B9F9369CC85:1371778250::::::a::::::23:
fpr:::::::::D73B9191F0AF110B229FF242EE1A8B9F9369CC85:

这个输出是稳定的,所以您可以只查找第一个 uid 要素:

gpg --with-colons -k <fingerprint> |
  awk -F: '$1=="uid" {print $10; exit}'

Lars LastName <lars@...>

--用冒号 here .