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从嵌套数组php获取信息

json arrays php

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Jesse Orange · 技术社区 · 7 年前

我正在调用API

我将响应作为关联数组,以便使用:

$field = $response['nameOfKey'];

但是,键的一些值本身是数组,如下所示:

{
  "Title": "Mr",
  "Forenames": "Steve",
  "Surname": "Williams",
  "CountryOfBirth": 1,
  "EmailAddress": "john.doe@email.com",
  "EmailType": "Personal",
  "BirthDate": "\/Date(632880000000)\/",
  "Suffix": null,
  "NationalInsuranceNumber": null,
  "PrimaryAddress": {
    "Address1": "Flat 1",
    "Address2": "Oxford Street",
    "City": "London",
    "County": "London",
    "Postcode": "L12456",
    "Country": 1
  },
  "AdditionalAddresses": [
    {
      "Address1": null,
      "Address2": null,
      "City": null,
      "County": null,
      "Postcode": null,
      "Country": 0,
      "AddressType": 0
    }
  ],
  "PrimaryTelephone": {
    "Number": "123456789",
    "DialingCode": 1,
    "TelephoneType": 1
  },
  "AdditionalTelephone": [
    {
      "Number": "223456789",
      "DialingCode": 2,
      "TelephoneType": 2
    }
  ],
  "BankAccount": {
    "AccountName": "John Doe Account",
    "AccountNumber": "123456789",
    "SortCode": "123456"
  },
  "PrimaryCitizenship": {
    "CountryOfResidency": 1,
    "TaxIdentificationNumber": "AB12CD34EF56"
  },
  "AdditionalCitizenship": [
    {
      "CountryOfResidency": 0,
      "TaxIdentificationNumber": null
    }
  ],
  "ExternalCustomerId": "91",
  "ExternalPlanId": "91",
  "PlanType": 10
}

所以现在我可以用名字 $forename = $decodedResponse["Forenames"]; 但我对试图从内部数组中获取值感到非常困惑。

我想我可以这样做:

foreach($decodedResponse as $data)
        {
            foreach($data['TelephoneNumbers'] as $tel)
            {
                echo $tel['Number']; die();
            }
}

本质上,循环原始关联数组,然后循环特定键以获取其值。

1 回复 | 直到 7 年前

1

Jirka Hrazdil 7 年前

您应该使用 foreach 对于以下阵列项: AdditionalAddresses , AdditionalTelephone 和 AdditionalCitizenship . 否则,只需链阵列键。参见示例:

$forename = $decodedResponse['Forenames'];
$address2 = $decodedResponse['PrimaryAddress']['Address2'];

foreach ($decodedResponse['AdditionalTelephone'] as $tel) {
  echo $tel['Number'];
}