代码之家 › 专栏 › 技术社区 › Jaquarh

在按其他键排序之前,如何按键对PHP数组进行分组?

laravel-8 laravel php

-1

Jaquarh · 技术社区 · 4 年前

我有一个包含密钥的数组 counted placement 在分类之前,我试图对其进行分组。数组应首先按 计数 然后,对于每个副本 ,然后应按 安置 .

$array = [
    [
        'id' => 1,
        'placement' => 8,
        'counted' => 3
        'user' => ['name' => 'foo'],
    ],
    [
        'id' => 2,
        'placement' => 5,
        'counted' => 3
        'user' => ['name' => 'bar'],
    ],
    [
        'id' => 3,
        'placement' => 1,
        'counted' => 2
        'user' => ['name' => 'foobar'],
    ]
];

我在这里的预期输出是:

$array = [
    [
        'id' => 2,
        'placement' => 5,
        'counted' => 3
        'user' => ['name' => 'bar'],
    ],
    [
        'id' => 1,
        'placement' => 8,
        'counted' => 3
        'user' => ['name' => 'foo'],
    ],
    [
        'id' => 3,
        'placement' => 1,
        'counted' => 2
        'user' => ['name' => 'foobar'],
    ]
];

我已经试过了 usort 为实现这一目标:

usort($array, fn($a, $b) => ((int)$a['placement'] <=> (int)$b['counted']) * -1);

2 回复 | 直到 4 年前

1

2

Hung Pham 4 年前

因为你更喜欢使用usort,所以这是我的答案

$array = [
    [
        'id' => 1,
        'placement' => 8,
        'counted' => 3,
        'user' => ['name' => 'foo'],
    ],
    [
        'id' => 2,
        'placement' => 5,
        'counted' => 3,
        'user' => ['name' => 'bar'],
    ],
    [
        'id' => 3,
        'placement' => 1,
        'counted' => 2,
        'user' => ['name' => 'foobar'],
    ]
];


usort($array, function ($a, $b) {
    if ($a['counted'] < $b['counted']) {
        return 1;
    }

    if ($a['counted'] === $b['counted'] && $a['placement'] > $b['placement']) {
        return 1;
    }
});

2

1

rubys 4 年前

如果你不在乎效率,你可以这样写

collect($array)
    ->sortByDesc('counted')
    ->groupBy('counted')
    ->map(function ($group) {
        return $group->sortBy('placement');
    })
    ->flatten(1)
    ->toArray()