必须根据MySQL语法要求确定计算字段的别名
SELECT Course_ID, Question_ID, Answer, (
CASE
WHEN Question_ID = 77 THEN "1"
WHEN Question_ID = 78 THEN "2"
WHEN Question_ID = 79 THEN "3"
WHEN Question_ID = 80 THEN "4"
WHEN Question_ID = 81 THEN "5"
WHEN Question_ID = 82 THEN "6"
ELSE "Undefined HIP"
END) as HIP
FROM proposals.new_gen_ed_answers
WHERE Answer = 1
SELECT Course_ID, Question_ID, Answer, (
CASE
WHEN Question_ID = 77 THEN "1"
WHEN Question_ID = 78 THEN "2"
WHEN Question_ID = 79 THEN "3"
WHEN Question_ID = 80 THEN "4"
WHEN Question_ID = 81 THEN "5"
WHEN Question_ID = 82 THEN "6"
ELSE "Undefined HIP"
END) HIP
FROM proposals.new_gen_ed_answers
WHERE Answer = 1