Neo4j-检查顺序路径是否存在

您可以尝试为匹配整个路径手动构建查询,并使用函数执行它 apoc.cypher.run :

WITH ['a', 'b', 'c', 'd'] AS search_list
WITH search_list,
     'MATCH path = ' +  
     REDUCE(c = '', i in range(0, size(search_list) - 2) | 
            c + '(:Node {prop: $props[' + i + ']})-->'
     ) +
     '(:Node {prop: $props[' + (size(search_list) - 1)  +']}) ' +
     'RETURN count(path) as pathCount' AS cypherQuery
CALL apoc.cypher.run(cypherQuery, {props: search_list}) YIELD value
RETURN CASE WHEN value.pathCount > 0 
            THEN true 
            ELSE false 
       END AS pathExists

parameter 名单的长度是 4 ,此查询将首先搜索长度为4且具有所需开始和结束节点的所有路径(以缩小候选路径),然后过滤路径的内部节点:

MATCH p=(a:Node {prop: $props[0]})-[*4]->(b:Node {prop: $props[-1]})
WITH p, NODES(p)[1..-2] AS midNodes
WHERE ALL(i IN RANGE(1, SIZE(midNodes)) WHERE midNodes[i-1] = $props[i])
RETURN p;

index :Node(prop)

如果此查询不返回任何内容,则没有匹配的路径。