我可以在awk中进行基于时间的进度吗?

awk '
function prtDot() {
    currTime = systime()
    if ( (currTime - prevTime) > 60 ) {
        printf "." | "cat>&2"
        prevTime = currTime
    }
}
{ print $0; prtDot() }
END { print "" | "cat>&2" }
'

e、 g.打印a .

$ cat tst.awk
function prtDot() {
    currTime = systime()
    if ( (currTime - prevTime) > 10 ) {
        printf "." | "cat>&2"
        prevTime = currTime
    }
}
{ printf "%s",$0%10 | "cat>&2"; prtDot() }
END { print "" | "cat>&2" }

$ i=0; while (( i < 50 )); do echo $((++i)); sleep 1; done | awk -f tst.awk
1.2345678901.23456789012.3456789012.34567890123.4567890

$ i=0; while (( i < 50 )); do echo $((++i)); sleep 3; done | awk -f tst.awk
1.2345.6789.0123.4567.8901.2345.6789.0123.4567.8901.2345.6789.0

systime() 在awk中被呼叫。