我试图注册同一接口的多个实现…然后…使用setter在我的应用程序实例上设置属性。我尝试过多个在线示例,总是将同一个实例插入到2个应用程序属性中。

• 注:我在网上试过很多例子,下面只是最新版本

例如。。。
当我在快速监视中查看应用程序对象时,会得到以下信息

我的配置:
很明显,我已经分析了所有其他的物体…

public ContainerRegistry()
{
    Scan(
        scan =>
        {
            scan.TheCallingAssembly();
            scan.WithDefaultConventions();
            scan.LookForRegistries();
            scan.AssembliesFromApplicationBaseDirectory(f => f.FullName.StartsWith("Demo.Common", true, null));
            scan.AssembliesFromApplicationBaseDirectory(f => f.FullName.StartsWith("XXX.XXX.MeasurementContracts", true, null));
            scan.AddAllTypesOf(typeof(IMeasurementContractsApplication));
            scan.AddAllTypesOf(typeof(IInstanceProvider));
            scan.SingleImplementationsOfInterface();
        });

    // --------
    // NAMED INSTANCES - IInstanceProvider
    For<IInstanceProvider>().Use<DistributionListProvider>();
    For<IInstanceProvider>().Add<FirstDeliveryNoticeDocumentRecallManager>().Named("firstDeliveryNoticeDocumentRecallManager");

    // --------
    // APPLICATION
    For<IMeasurementContractsApplication>().Use<MeasurementContractsApplication>()

        // Component
        .Setter(x => x.DistributionListProvider).Is<DistributionListProvider>()
        .Setter(x => x.FirstDeliveryNoticeDocumentRecallManager).IsNamedInstance("firstDeliveryNoticeDocumentRecallManager");
}

应用示例:
很明显,我已经分析了所有其他的物体…

public class MeasurementContractsApplication : IMeasurementContractsApplication
{
    [SetterProperty]
    public IMeasurementContractsUnitOfWork UnitOfWork { get; set; }

    [SetterProperty]
    public IInstanceProvider DistributionListProvider { get; set; }

    [SetterProperty]
    public IInstanceProvider FirstDeliveryNoticeDocumentRecallProvider { get; set; }
}

iInstanceProvider的:

public class DistributionListProvider : ProviderBase, IInstanceProvider
{
    // Purposely left-out Properties, Methods etc.
}

public class FirstDeliveryNoticeDocumentAdminUpdateProvider : ProviderBase, IInstanceProvider
{
    // Purposely left-out Properties, Methods etc.
}

public class ProviderBase
{
    [SetterProperty]
    public IMeasurementContractsUnitOfWork UnitOfWork { get; set; }

}

————————————————————————————————————————--
更新:从向我提出的问题
为了把事情降到一个非常基本的水平…我决定实现一个最小的2个类集合来尝试以下建议:

public interface ITesting
{
    string Name();
}

public class Foo : ITesting
{
    public string Name()
    {
        return string.Empty;
    }
}

public class Bar : ITesting
{
    public string Name()
    {
        return string.Empty;
    }
}

public ContainerRegistry()
{
    Scan(
        scan =>
        {
            scan.TheCallingAssembly();
            scan.WithDefaultConventions();
            scan.LookForRegistries();
            scan.AssembliesFromApplicationBaseDirectory(f => f.FullName.StartsWith("Demo.Common", true, null));
            scan.AssembliesFromApplicationBaseDirectory(f => f.FullName.StartsWith("XXX.MeasurementContracts", true, null));
            scan.AddAllTypesOf(typeof(IMeasurementContractsApplication));
            scan.AddAllTypesOf(typeof(IManager<>));
            scan.AddAllTypesOf(typeof(IDocumentDependency));
            scan.AddAllTypesOf(typeof(IDataItemProviderFor<>));
            scan.AddAllTypesOf(typeof(IDatasetBuilderFor<>));
            scan.AddAllTypesOf(typeof(IXmlTransformerFor<>));
            scan.AddAllTypesOf(typeof(IWorkflowProvider));
            scan.AddAllTypesOf(typeof(IInstanceProvider));
            scan.AddAllTypesOf(typeof(IPdfConverterClient));
            scan.AddAllTypesOf(typeof(IReportFor<>));
            scan.AddAllTypesOf(typeof(IAdminUpdateCommandFor<>));
            scan.AddAllTypesOf(typeof(ITesting));
            scan.SingleImplementationsOfInterface();
        });

         Component Providers
        For<IMeasurementContractsApplication>().Use<MeasurementContractsApplication>()
            Setter(x => x.Bar).Is<Bar>()
            Setter(x => x.Foo).Is<Foo>();
}

两种结果中的一种总是会发生

1. 属性为空
2. 我收到以下错误消息

“未注册默认实例,并且无法自动 为类型“iInstanceProvider”确定没有默认实例 指定。”

问:目标实现位于何处?

XXX.测量合同.业务
包含“containerRegistry”和所有类、接口等。

xxx.measurementcontracts.web网站
包含“structuremapmvcconfig”、“ioc”初始值设定项及其自己的“defaultregistry”

测量合同.单元试验
将业务“containerRegistry”添加到其“ioc”初始值设定项中…然后添加自己的“containerRegistry”。

尝试:尝试命名注册 我在“containerRegistry”中添加了以下内容,虽然它们都是填充的……但它们都是“bar”类型的

// Component Providers
For<ITesting>().Use<Bar>().Named("Bar");
For<ITesting>().Add<Foo>().Named("Foo");

// Component Providers
For<IMeasurementContractsApplication>().Use<MeasurementContractsApplication>()
     .Setter(x => x.Bar).Is<Bar>()
     .Setter(x => x.Foo).Is<Foo>();

如何解决“foo”? 我也尝试过“.setter(x=>x.foo).is(c=>c.getInstance(“foo”));”

分析:使用container.whatDoiHave() 好的,使用“whatDoiHave”显示我已经正确配置了“itesting”实例。

• 瞬态-xxx.measurementcontracts.business.providers.bar('bar')-bar(默认)
• 瞬态-xxx.measurementcontracts.business.providers.foo('foo')-foo

如何将“foo”和“bar”分解为它们各自的属性?