代码之家 › 专栏 › 技术社区 › BrianMichaels

如何从c中的方法返回两个字符串数组#

BrianMichaels · 技术社区 · 6 年前

 using System;
 using System.Linq;

 namespace ConsoleApp1
 {
   class Program
   {
    static void Main(string[] args)
    {
        string[] names1 = new string[] { "Ava", "Emma", "Olivia" };
        string[] names2 = new string[] { "Olivia", "Sophia", "Emma" };
        Console.WriteLine(string.Join(", ", Program.UniqueNames(names1, names2)));
    }

    public static string[] UniqueNames(string[] names1, string[] names2)
    {

        names1 = names1.Where(s => !names2.Contains(s)).ToArray();
        names2 = names2.Where(s => !names1.Contains(s)).ToArray();
        return (names1, names2);

    }
  }
}

3 回复 | 直到 6 年前

Igor 6 年前

https://docs.microsoft.com/en-us/dotnet/csharp/tuples

    ...
    (names1, names2) = Program.UniqueNames(names1, names2);
    Console.WriteLine(string.Join(", ", names1.Union(names2)));
}

public static (string[], string[]) UniqueNames(string[] names1, string[] names2)
{
    names1 = names1.Where(s => !names2.Contains(s)).ToArray();
    names2 = names2.Where(s => !names1.Contains(s)).ToArray();
    return (names1, names2);
}

rfmodulator 6 年前

从C#7.0版开始,元组的支持如下:

public static (string[], string[]) UniqueNames(string[] names1, string[] names2){/*â¦*/}

Patrick Tucci 6 年前

有几种方法可以实现这一点,但是没有必要使用单独的方法。可能更容易 Union() 使用Linq的列表:

string[] names1 = new string[] { "Ava", "Emma", "Olivia" };
string[] names2 = new string[] { "Olivia", "Sophia", "Emma" };
var unique = names1.Union(names2);
Console.WriteLine(string.Join(", ", unique))

推荐文章

SpaceCowboy74 Mohammad Aghazadeh · 使用Fluent Validation比较数组中的值

1 年前