以更人性化的方式编组字符**

我在C#中有以下接口方法声明:

[ComVisible(true), ComImport, SuppressUnmanagedCodeSecurity,
Guid("A668B8F2-BA87-4F63-9D41-768F7DE9C50E"),
InterfaceType(ComInterfaceType.InterfaceIsIUnknown)]
public interface ILAVAudioStatus
{
    [PreserveSig]
    int GetOutputDetails(out IntPtr pOutputFormat, out int pnChannels, out int pSampleRate, out uint pChannelMask);
}

pOutputformat实际上是C中的char**++

我需要做一个 Marshal.PtrToStringAnsi(pOutputformat) 以获得实际字符串。

是否有一些编组属性可以将pOutputformat直接转换为输出字符串,而不是使用IntPtr?

这是C++方法的作用:

HRESULT CLAVAudio::GetOutputDetails(const char **pOutputFormat, int *pnChannels, int *pSampleRate, DWORD *pChannelMask)
{
  if(!m_pOutput || m_pOutput->IsConnected() == FALSE) {
    return E_UNEXPECTED;
  }
  if (m_avBSContext) {
    if (pOutputFormat) {
      *pOutputFormat = get_sample_format_desc(SampleFormat_Bitstream);
    }
    return S_FALSE;
  }
  if (pOutputFormat) {
    *pOutputFormat = get_sample_format_desc(m_OutputQueue.sfFormat);
  }
  if (pnChannels) {
    *pnChannels = m_OutputQueue.wChannels;
  }
  if (pSampleRate) {
    *pSampleRate = m_OutputQueue.dwSamplesPerSec;
  }
  if (pChannelMask) {
    *pChannelMask = m_OutputQueue.dwChannelMask;
  }
  return S_OK;
}