Golang httpRouter在与函数片一起使用时返回最后一个响应

我正在努力实现 expressjs 喜欢的功能 httprouter 包裹 我创建了一个结构 type mounter

type Mounter struct {
    BasePath string
    Routes   []*Route
}

及 Route 表示子例程的结构

type Route struct {
    Path   string
    Method string
    Func   Handle
}

type Handle func(http.ResponseWriter, *http.Request, Params)

type Params interface{}

我有一个 NewRoutes 函数,这是我想从expressjs新路由中移植的主要功能,它与 express.Router

func NewRoutes(base string) (mounter *Mounter) {
    mounter = &Mounter{
        BasePath: base,
    }
    return
}

我有 get post put delete *Mounter

//GET request handler
func (mounter *Mounter) GET(path string, Func Handle) {
    mounter.Routes = append(mounter.Routes, &Route{path, "get", Func})
}

//POST request handler
func (mounter *Mounter) POST(path string, Func Handle) {
    mounter.Routes = append(mounter.Routes, &Route{path, "post", Func})
}

//PUT request handler
func (mounter *Mounter) PUT(path string, Func Handle) {
    mounter.Routes = append(mounter.Routes, &Route{path, "put", Func})
}

//DELETE request handler
func (mounter *Mounter) DELETE(path string, Func Handle) {
    mounter.Routes = append(mounter.Routes, &Route{path, "delete", Func})
}

最后,我有一个挂载方法,将路由器挂载到实际路由器

func (mounter *Mounter) Mount(router *rtr.Router) {
    mounter.BasePath = strings.TrimSuffix(mounter.BasePath, "/")
    for _, route := range mounter.Routes {
        path := route.Path
        if !strings.HasSuffix(path, "/") {
            path += "/"
        }
        path = mounter.BasePath + path
        switch strings.ToLower(route.Method) {
        case "get":
            router.GET(path, func(res http.ResponseWriter, req *http.Request, params rtr.Params) {
                route.Func(res, req, params)
            })
        case "post":
            router.POST(path, func(res http.ResponseWriter, req *http.Request, params rtr.Params) {
                route.Func(res, req, params)
            })
        case "delete":
            router.DELETE(path, func(res http.ResponseWriter, req *http.Request, params rtr.Params) {
                route.Func(res, req, params)
            })
        case "put":
            router.PUT(path, func(res http.ResponseWriter, req *http.Request, params rtr.Params) {
                route.Func(res, req, params)
            })
        }
    }
}

一切都很好,方法也很好。如果我尝试向get端点发送post请求,它会给出一个很好的404,但唯一的问题是它总是使用最后添加的成员的处理程序进行响应,而不管子路径如何

package api
var ApiRouter = express.NewRoutes("/api/")

func init() {
    ApiRouter.GET("/", func(res http.ResponseWriter, req *http.Request, _ express.Params) {
        fmt.Fprintln(res, "testget/")
    })
    ApiRouter.GET("/pt", func(res http.ResponseWriter, req *http.Request, _ express.Params) {
        fmt.Fprintln(res, "pt")
    })
    ApiRouter.POST("/test", func(res http.ResponseWriter, req *http.Request, _ express.Params) {
        fmt.Fprintln(res, "test/post")
    })
}

package main
func main() {
    router := express.New()
    api.ApiRouter.Mount(router)
    for _, route := range api.ApiRouter.Routes {
        fmt.Println(*route)
    }
    router.ServeFiles("/public/*filepath", http.Dir("./public/"))
    http.ListenAndServe(":1024", router)
}

总是会回应 test/post 和 range 我以上所做的是为了测试目的 那么,你知道为什么它总是使用相同的函数来响应,但却能完美地识别路径吗?