向存储过程传递分隔字符串以搜索数据库

由于不能使用表参数(在SQLServer2008上不可用),请尝试传入CSV字符串,并让存储过程将其拆分为行。

"Arrays and Lists in SQL Server 2005 and Beyond, When Table Value Parameters Do Not Cut it" by Erland Sommarskog

你需要创建一个分割函数。这就是拆分函数的用法:

SELECT
    *
    FROM YourTable                               y
    INNER JOIN dbo.yourSplitFunction(@Parameter) s ON y.ID=s.Value

I prefer the number table approach to split a string in TSQL 但是在SQLServer中有很多方法可以分割字符串,请参阅前面的链接,其中解释了每种方法的优缺点。

要使Numbers表方法工作,您需要执行一次性表设置,这将创建一个表 Numbers 包含从1到10000行的:

SELECT TOP 10000 IDENTITY(int,1,1) AS Number
    INTO Numbers
    FROM sys.objects s1
    CROSS JOIN sys.objects s2
ALTER TABLE Numbers ADD CONSTRAINT PK_Numbers PRIMARY KEY CLUSTERED (Number)

设置完数字表后,创建此拆分函数:

CREATE FUNCTION [dbo].[FN_ListToTable]
(
     @SplitOn  char(1)      --REQUIRED, the character to split the @List string on
    ,@List     varchar(8000)--REQUIRED, the list to split apart
)
RETURNS TABLE
AS
RETURN 
(   ----------------
    --SINGLE QUERY-- --this will not return empty rows
    ----------------
    SELECT
        ListValue
        FROM (SELECT
                  LTRIM(RTRIM(SUBSTRING(List2, number+1, CHARINDEX(@SplitOn, List2, number+1)-number - 1))) AS ListValue
                  FROM (
                           SELECT @SplitOn + @List + @SplitOn AS List2
                       ) AS dt
                      INNER JOIN Numbers n ON n.Number < LEN(dt.List2)
                  WHERE SUBSTRING(List2, number, 1) = @SplitOn
             ) dt2
        WHERE ListValue IS NOT NULL AND ListValue!=''
);
GO 

CREATE TABLE YourTable (PK int, col1 varchar(20), col2 varchar(20), col3 varchar(20))
--data from question
INSERT INTO YourTable VALUES (1,'hello xyz','abc is my last name','and i''m a developer')
INSERT INTO YourTable VALUES (2,'hello xyz',null,'and i''m a developer')

CREATE PROCEDURE YourProcedure
(
    @keywords   varchar(1000)
)
AS

SELECT
    @keywords AS KeyWords,y.* 
    FROM (SELECT
              t.PK
              FROM dbo.FN_ListToTable(' ',@keywords) dt
                  INNER JOIN YourTable             t ON  t.col1 LIKE '%'+dt.ListValue+'%' OR t.col2 LIKE '%'+dt.ListValue+'%' OR t.col3 LIKE '%'+dt.ListValue+'%'
              GROUP BY t.PK
              HAVING COUNT(t.PK)=(SELECT COUNT(*) AS CountOf FROM dbo.FN_ListToTable(' ',@keywords))
         ) dt
        INNER JOIN YourTable y ON dt.PK=y.PK
GO

--from question   
EXEC YourProcedure 'xyz developer'-- returns 2 rows
EXEC YourProcedure 'xyz abc'-- returns 1 row
EXEC YourProcedure 'abc developer'-- returns 1 row
EXEC YourProcedure 'hello'--  returns 2 rows
EXEC YourProcedure 'hello developer'--  returns 2 rows
EXEC YourProcedure 'xyz'-- returns 2 rows

输出:

KeyWords       PK    col1       col2                 col3
-------------- ----- ---------- -------------------- --------------------
xyz developer  1     hello xyz  abc is my last name  and i'm a developer
xyz developer  2     hello xyz  NULL                 and i'm a developer

(2 row(s) affected)

KeyWords       PK    col1       col2                 col3
-------------- ----- ---------- -------------------- --------------------
xyz abc        1     hello xyz  abc is my last name  and i'm a developer

(1 row(s) affected)

KeyWords       PK    col1       col2                 col3
-------------- ----- ---------- -------------------- --------------------
abc developer  1     hello xyz  abc is my last name  and i'm a developer

(1 row(s) affected)

KeyWords       PK    col1       col2                 col3
-------------- ----- ---------- -------------------- --------------------
hello          1     hello xyz  abc is my last name  and i'm a developer
hello          2     hello xyz  NULL                 and i'm a developer

(2 row(s) affected)

KeyWords        PK    col1       col2                 col3
--------------- ----- ---------- -------------------- --------------------
hello developer 1     hello xyz  abc is my last name  and i'm a developer
hello developer 2     hello xyz  NULL                 and i'm a developer

(2 row(s) affected)

KeyWords       PK    col1       col2                 col3
-------------- ----- ---------- -------------------- --------------------
xyz            1     hello xyz  abc is my last name  and i'm a developer
xyz            2     hello xyz  NULL                 and i'm a developer

(2 row(s) affected)

select firstname, lastname from @test t1
inner join persondata t on t.firstname like '%' + t1.x + '%' or t.lastname like '%' + t1.x + '%'
group by firstname, lastname
having count(distinct x) = (select count(*) from @test)