林福-看不懂怎么做

刚找到林福-看起来很不错,但我不能 看看如何做我想做的事情-这是mixin的多重继承(构图/委托,就像我在VB5/6天中说的-当我有一个工具来生成冗长的重复委托代码-当我寻找一个C#等价物时,我找到了LinFu)。

public class Person : NEOtherBase, IName, IAge 
{

    public Person()
    {

    }

    public Person(string name, int age)
    {
        Name = name;
        Age = age;
    }

    //Name "Mixin" - you'd need this code in any object that wanted to
    //use the NameObject to implement IName
    private NameObject _nameObj = new NameObject();

    public string Name
    {
        get { return _nameObj.Name; }
        set { _nameObj.Name = value; }
    }
    //--------------------

    //Age "Mixin" you'd need this code in any object that wanted to
    //use the AgeObject to implement IAge
    private AgeObject _ageObj = new AgeObject();

    public int Age
    {
        get { return _ageObj.Age; }
        set { _ageObj.Age = value; }
    }
    //------------------

}

public interface IName
{
    string Name { get; set; }
}

public class NameObject : IName
{
    public NameObject()
    {}

    public NameObject(string name)
    {
        _name = name;
    }

    private string _name;
    public string Name { get { return _name; } set { _name = value; } }

}

public interface IAge 
{
    int Age { get; set; }
}

public class AgeObject : IAge
{
    public AgeObject()
    {}

    public AgeObject(int age)
    {
        _age = age;
    }

    private int _age;
    public int Age { get { return _age; } set { _age = value; } }

}

想象一下有更多属性的对象,在更多的“子类”中使用,你就会开始看到单调乏味。代码格伦工具实际上是 好的 ...

所以,临福。。。。 班 (如上)-临福式的做法是什么?或者我错过了全部要点?

编辑:我需要能够这样做的类已经是子类。

DynamicObject dynamic = new DynamicObject();

IPerson person = null;

// This will return false
bool isPerson = dynamic.LooksLike<IPerson>();

// Implement IPerson
dynamic.MixWith(new HasAge(18));
dynamic.MixWith(new Nameable("Me"));

// Now that it’s implemented, this
// will be true
isPerson = dynamic.LooksLike<IPerson>();

if (isPerson)
    person = dynamic.CreateDuck<IPerson>();

// This will return “Me”
string name = person.Name;

// This will return ‘18’
int age = person.Age;