您可以从范围的元组中分配域:
var tup = (1..10,2..20);
var D : domain(2) = tup;
这个
param
修饰符会起作用。下面是一个示例,我在其中引入一个域,创建一个更大的一维域,并在其上返回一个数组。
proc dimensionalExpansion( dom : domain ) {
// Get and expand rank
param oldRank = dom.rank;
param newRank = oldRank+1;
// create tuple of size newRank to store each dimensions ranges
var ranges : newRank*range(dom.idxType, BoundedRangeType.bounded, dom.stridable);
// copy range from domain
for i in 1..#oldRank do ranges[i] = dom.dim(i);
// use last range from domain as our last range
ranges[newRank] = ranges[oldRank];
// Create new domain from ranges tuple
var D: domain(newRank) = ranges;
// Create array
var arr: [D] int;
// Putting some arbitrary values into the array;
for idx in D {
arr[idx] = if newRank > 1 then idx[newRank] - idx[1] else idx;
}
return arr;
}
writeln( "==================" );
writeln( dimensionalExpansion( {1..3} ) );
writeln( "==================" );
writeln( dimensionalExpansion( {1..3,1..3} ) );
writeln( "==================" );
writeln( dimensionalExpansion( {1..3,1..3,1..3} ) );
Running TIO Instance