Xquery递归

我有一个关于Xpath的问题,这是我非常有经验的。我正在做一个作业,我应该反转所有元素,以便音乐标签内的子元素成为属性,并且属性成为子元素。

是否可以使用Xpath实现这一点,我应该如何实现?还是编写XML文件的DTD并在Xquery中编写解决方案更好?

我的XML如下所示:

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<music>

<song genre="rocknroll" album="1134" artist="249" id="11992"><name>The Sound of Silence</name><nr>1</nr></song>
<song genre="rocknroll" album="4329" artist="932" id="34311"><name>Material Girl</name><nr>2</nr></song>
<song genre="hardrock" album="5293" artist="1167" id="54312"><name>Paradise City</name><nr>1</nr></song>
<song genre="classic" album="7002" artist="156" id="78340"><name>La Primavera</name><nr>1</nr></song>

<artist id="249" isband="yes">Simon and Garfunkel</artist>
<artist id="932" isband="no">Madonna</artist>
<artist id="1167" isband="yes">Guns N'Roses</artist>
<artist id="156" isband="no">Antonio Vivaldi</artist>

<album issued="1964" id="1134" label="Columbia Records">Wednesday Morning, 3 AM</album>
<album issued="1984" id="4392" label="Sire Records">Like A Virgin</album>
<album issued="1988" id="5293" label="Geffen Records">Appetite for Destruction</album>
<album issued="2004" id="7002" label="Naxos Records" performers="Wiener Philharmoniker">Le Quattro Stagioni</album>

</music>

提前感谢您的帮助。