C#:参数化字符串,仅在“full”参数之间有空格?

string.Format("{0} {1} {2}", first, middle, last).Replace("  "," ")

也许值得一试 Name 具有 Full 处理该逻辑的属性(即将打印 "John Smith" 如果没有中间名或 "John A. Smith" 如果有的话)。

那么您的代码将是:

var name = new Name(first, middle, last);
var message = string.Format("Hello {0}", name.Full);

LastFirstMiddle 财产(以获得 "Smith, John A." 格式字符串)和任何其他对 班级。

"Hello {0} {1}{3}{2}"

哪里

{3} = param1.IsNullOrEmpty() ? "" : " "

实现这一点的一种方法是将空格放入参数字符串中。例如(仅以名字和姓氏为例)

Console.WriteLine("Hello {0}{1}{2}",
  firstName,
  String.IsNullOrEmpty(firstName) ? String.Empty : " ", 
  lastName);

var hello =
    (from name in new[] { "Hello", firstName, middleName, lastName }
     where !string.IsNullOrEmpty(name))
     .Aggregate((xs, x) => xs + " " + x);

或

var hello = string.Join(" ", 
    (from name in new[] { "Hello", firstName, middleName, lastName }
     where !string.IsNullOrEmpty(name))
     .ToArray());

public string LogicFullName(string fName)
    {
        string logicName = String.Empty;
        string[] splitFullName = fName.Trim().Split(' ');
        for (int i = 0; i < splitFullName.Length; i++)
        {
            if (logicName == String.Empty && i == 0)
            {
                logicName = splitFullName[i].Trim();
            }
            else
            {
                if (splitFullName[i] != String.Empty)
                    logicName = logicName + " " + splitFullName[i].Trim();
            }
        }
        return logicName;
     }