具有多个提交选项的HTML表单

<input type="submit" name="delete[1]" value="delete">

if (isset($_POST['delete'])) $id=key($_POST['delete']);

它似乎总是提交最后一个ID

它提交了所有的名字,但是因为名字不是以 [] ,PHP按最后一个丢弃所有。

如果我正确理解你的目标,你有两个主要的选择。

2. Encode the id value into the name of the submit button

您可以去掉隐藏字段,并将提交按钮命名为:

<input type="submit" name="delete[1]" />
<input type="submit" name="delete[2]" />
<input type="submit" name="delete[3]" />

然后

<?php

if (isset($_POST['delete'])) {
   $toDeleteId = key($_POST['delete']);
}