如何在按钮onclick被触发后保持alertdialog打开?

使用带有android:password=“true”按钮属性的EditText构建一个自定义对话框,然后手动设置onClick listener按钮,并显式选择在其中执行的操作。

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout 
    xmlns:android="http://schemas.android.com/apk/res/android" 
    android:layout_width="wrap_content" 
    android:layout_height="wrap_content" 
    android:orientation="vertical">

    <EditText 
        android:layout_width="fill_parent" 
        android:layout_height="wrap_content" 
        android:minWidth="180dip" 
        android:digits="1234567890" 
        android:maxLength="4" 
        android:password="true"/>

    <LinearLayout 
        android:layout_width="fill_parent" 
        android:layout_height="wrap_content" 
        android:orientation="horizontal">

        <Button 
            android:id="@+id/Accept" 
            android:layout_width="fill_parent" 
            android:layout_height="wrap_content" 
            android:text="Accept"/>

    </LinearLayout> 
</LinearLayout> 

final Dialog dialog = new Dialog(RealizarPago.this);
dialog.setContentView(R.layout.custom_dialog);
dialog.setTitle("PIN number:");
dialog.setCancelable(true);

Button button = (Button) dialog.findViewById(R.id.Accept);
button.setOnClickListener(new OnClickListener() {
@Override
    public void onClick(View v) {
        if(password_wrong){ 
          // showToast
        } else{
          dialog.dismiss();
          // other stuff to do
        }
    }
}); 

dialog.show();  

不需要创建自定义类。您可以为AlertDialog注册View.OnClickListener。此侦听器不会关闭AlertDialog。这里的技巧是,您需要在对话框显示后注册侦听器,但是可以在OnShowListener中灵活地完成。您可以使用一个辅助布尔变量来检查是否已经执行了此操作,以便只执行一次:

    /*
     * Prepare the alert with a Builder.
     */
    AlertDialog.Builder b = new AlertDialog.Builder(this);

    b.setNegativeButton("Button", new DialogInterface.OnClickListener() {
        @Override
        public void onClick(DialogInterface dialog, int which) {}
    });
    this.alert = b.create();

    /*
     * Add an OnShowListener to change the OnClickListener on the
     * first time the alert is shown. Calling getButton() before
     * the alert is shown will return null. Then use a regular
     * View.OnClickListener for the button, which will not 
     * dismiss the AlertDialog after it has been called.
     */

    this.alertReady = false;
    alert.setOnShowListener(new DialogInterface.OnShowListener() {
        @Override
        public void onShow(DialogInterface dialog) {
            if (alertReady == false) {
                Button button = alert.getButton(DialogInterface.BUTTON_NEGATIVE);
                button.setOnClickListener(new View.OnClickListener() {
                    @Override
                    public void onClick(View v) {
                        //do something
                    }
                });
                alertReady = true;
            }
        }
    });

部分解决方案由 http://groups.google.com/group/android-developers/browse_thread/thread/fb56c8721b850124#

您可以如下设置OnClickListener以保持对话框打开:

public class MyDialog extends AlertDialog {
    public MyDialog(Context context) {
        super(context);
        setMessage("Hello");
        setButton(AlertDialog.BUTTON_POSITIVE, "Ok", (new DialogInterface.OnClickListener() {
            @Override
            public void onClick(DialogInterface dialog, int which) {
                // this will never be called
            }
        });
    }

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);

        getButton(AlertDialog.BUTTON_POSITIVE).setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {
                if (ok) {
                    // do something
                    dismiss();
                } else {
                    Toast.makeText(getContext(), "when you see this message, the dialog should stay open", Toast.LENGTH_SHORT).show();
                }
            }
        });
    }
}

您可以继续使用已有的对话框,只需在onClick()中放置一个if子句

if(pin_check_method){  //pin_check_method should be a boolean returned method
     //close the Dialog, then continue
     }
   else{
     //dont put the dialog.dismiss() in here, put instead
    Toast.makeText(getApplicationContext(),"Invalid pin, please try again",Toast.LENGTH_LONG).show();
}

现在,要使用这段代码,只需调用text.setText(“”),并在这里输入所需的文本

TextView text = (TextView) findViewById(R.id.dialog);

你错过了事实上

dialog.findViewById

这与对话框的名称无关,在我的示例中,它恰好是相同的名称。

<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
                android:id="@+id/layout_root" 
                android:layout_width="fill_parent" 
                android:layout_height="fill_parent" 
                >

    <TextView android:id="@+id/text"
              android:layout_height="wrap_content"
              android:textColor="#FFF"
              android:layout_centerHorizontal="true"
              android:layout_width="wrap_content"/>



    <Button android:text="Continue" 
            android:id="@+id/Button01" 
            android:layout_width="fill_parent" 
            android:layout_height="wrap_content" android:layout_below="@+id/text">
             </Button>

</RelativeLayout>

试试这个:

final AlertDialog alertDialog = new AlertDialog.Builder(context)
        .setView(v)
        .setTitle(R.string.my_title)
        .setPositiveButton(android.R.string.ok, null) //Set to null. We override the onclick
        .setNegativeButton(android.R.string.cancel, null)
        .create();

alertDialog.setOnShowListener(new DialogInterface.OnShowListener() {

    @Override
    public void onShow(DialogInterface dialog) {

        Button b = alertDialog.getButton(AlertDialog.BUTTON_POSITIVE);
        b.setOnClickListener(new View.OnClickListener() {

            @Override
            public void onClick(View view) {
                // TODO Do something

            }
        });
    }
});
alertDialog.show();

资料来源: Prevent Alertdialog from closing after button click

希望这有帮助!祝你好运!

同样的问题我在一个片段对话框。以下是我的犯罪/优雅解决方案:

<LinearLayout
        android:layout_width="match_parent"
        android:orientation="horizontal"
        android:layout_height="wrap_content">
        <Button
            android:layout_width="0dp"
            android:layout_weight="1"
            android:layout_height="wrap_content"
            android:id="@+id/button_cancel"
            style="@style/Widget.AppCompat.Button.Borderless.Colored"
            android:text="@android:string/cancel"
            android:layout_gravity="left"
            />
        <Button
            android:layout_width="0dp"
            android:layout_weight="1"
            android:layout_height="wrap_content"
            android:id="@+id/button_ok"
            style="@style/Widget.AppCompat.Button.Borderless.Colored"
            android:text="@android:string/ok"
            android:layout_gravity="right"
            />
    </LinearLayout>

然后在代码中处理它:

view.findViewById(R.id.button_ok).setOnClickListener(new View.OnClickListener() {
                @Override
                public void onClick(View view2) {
                    if (wannaClose)
                        dismiss();
                    else
                        //do stuff without closing!
                }
            });