Play framework 2.5.X中的递归

-skillList是一个列表[技能]

-技能是在模型中定义的对象

-skillObject。getChildrenList()返回列表[技能]

我想做的是能够显示这一点,但使用某种类型的递归,这样如果mylist的嵌套级别更改,我就不必更改整个模板。那么,有什么方法可以递归地做到这一点吗?

<div class="custom-dd dd dd-nodrag" id="nestable_list_1">
<ol class="dd-list">
@for(skill <- skillList) {
    <li class="dd-item">
        <div class="dd-handle dd-nodrag row">
            <span class="dd-nodrag" id="content_@skill.getCleanUri()"> @skill.getLabel() </span>
        </div>

    <ol class="dd-list">
    @for((child, indexChild) <- skill.getChildrenList().zipWithIndex) {
        <li class="dd-item" data-id="@indexChild">
            <div class="dd-handle dd-nodrag row">
                <span id="content_@child.getCleanUri()"> @child.getLabel() </span>
            </div>

            <ol class="dd-list">
            @for((grandChild, indexGrandChild) <- child.getChildrenList().zipWithIndex) {
                <li class="dd-item" data-id="@indexGrandChild">
                    <div class="dd-handle dd-nodrag row">
                        <span id="content_@grandChild.getCleanUri()"> @grandChild.getLabel() </span>
                    </div>

                </li>
            }


            <div class="text-left addNew" id="meta-@index"> 
                <span>
                    <button class="btn btn-icon w-xs plusBtn
                    btn-primary waves-effect waves-light toggleButton" data-toggle="modal" 
                    data-target="#custom-width-modal"> <i class="fa fa-plus" aria-hidden="true"></i> 
                    </button> 
                </span>
            </div>
            @(index = index + 1)

            </ol>
            </li>
    }

    </ol>
    </li>
}

</ol>