django重写身份验证登录方法

完成此方法。

URL。py公司

# separate my custom login from django default auth
path('accounts/login/', CustomLoginView.as_view(), name='login'), 
path('accounts/', include('django.contrib.auth.urls')),

意见。py公司

def custom_login(request, user, backend=None):
    """
    modificated generic.auth login.
    Send signal with extra parameter: previous [session_key]
    """

    # get previous seesion_key for signal 
    prev_session_key = request.session.session_key

    """ 
        original code

    """
    # send extra argument prev_session_key 
    user_logged_in.send(sender=user.__class__, request=request, user=user, prev_session_key=prev_session_key)

# custom class-based view overriden on LoginView
class CustomLoginView(LoginView):

    def form_valid(self, form):
        """Security check complete. Log the user in."""

        # changed default login
        custom_login(self.request, form.get_user())

        return HttpResponseRedirect(self.get_success_url())

当我基于default login()进行custom\u登录时,恐怕这不是最好的方法,因为我正在复制原始代码的一部分。也许这里最好用一个装饰师?