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php:对给定字符串中的单词实例进行排序和计数

php

16

superUntitled · 技术社区 · 15 年前

假设我收集了一些单词:

快乐美丽快乐线条梨子酒快乐线条摇滚快乐线条梨子

如何使用php计算字符串中每个单词的每个实例并将其输出到循环中:

There are $count instances of $word

这样上面的循环就会输出:

有4个快乐的例子。

有3个线条实例。

杜松子酒有两个例子。。。。

2 回复 | 直到 5 年前

1

53

Felix Kling 15 年前

str_word_count() 和 array_count_values() :

$str = 'happy beautiful happy lines pear gin happy lines rock happy lines pear ';
$words = array_count_values(str_word_count($str, 1));
print_r($words);

给予

Array
(
    [happy] => 4
    [beautiful] => 1
    [lines] => 3
    [pear] => 2
    [gin] => 1
    [rock] => 1
)

1 使函数返回所有找到的单词的数组。

要对条目进行排序,请使用 arsort()

arsort($words);
print_r($words);

Array
(
    [happy] => 4
    [lines] => 3
    [pear] => 2
    [rock] => 1
    [gin] => 1
    [beautiful] => 1
)

2

6

Tatu Ulmanen 15 年前

试试这个:

$words = explode(" ", "happy beautiful happy lines pear gin happy lines rock happy lines pear");
$result = array_combine($words, array_fill(0, count($words), 0));

foreach($words as $word) {
    $result[$word]++;
}

foreach($result as $word => $count) {
    echo "There are $count instances of $word.\n";
}

There are 4 instances of happy.
There are 1 instances of beautiful.
There are 3 instances of lines.
There are 2 instances of pear.
There are 1 instances of gin.
There are 1 instances of rock.