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如何在JSON对象数组中获取下个月的日期?

json arrays php

flash · 技术社区 · 4 年前

我有一个 php code 如下图所示,在每个月的第一天,我复制第二个JSON对象数组 (next_month) (current_month) .

在第二个JSON对象数组中 (下个月) ,我想订下个月的日期。这也将发生在每个月的第一天。目前我正在储存 nada . 让我们假设今天 1st day of November .

php代码:

$value = json_decode(file_get_contents('../hyt/dates.json'));
    
if ((date('j') == 1)) {
    $month = 11;
    $year = date('Y');
    $current_month_days = (date('t', strtotime($year . '-' . $month . '-01')));
    $next_month_days = (date('t', strtotime($year . '-' . ($month + 1) . '-01')));
    $value->current_month = $value->next_month;   // Line Y
    $value->next_month = array_fill(0, ($next_month_days), nada);    // Line Z 
}

JSON的当前外观 (dates.json)

{"current_month": ["2020-10-01", "2020-10-02", "2020-10-03", "2020-10-04", "2020-10-05", "2020-10-06", "2020-10-07", "2020-10-08", "2020-10-09", "2020-10-10", "2020-10-10", "2020-10-12", "2020-10-13", "2020-10-14", "2020-10-15", "2020-10-16", "2020-10-17", "2020-10-18", "2020-10-19", "2020-10-20", "2020-10-21", "2020-10-22", "2020-10-23", "2020-10-24", "2020-10-25", "2020-10-26", "2020-10-27", "2020-10-28", "2020-10-29", "2020-10-30","2020-10-31"], 
"next_month": ["2020-11-01", "2020-11-02", "2020-11-03", "2020-11-04", "2020-11-05", "2020-11-06", "2020-11-07", "2020-11-08", "2020-11-09", "2020-11-11", "2020-11-11", "2020-11-12", "2020-11-13", "2020-11-14", "2020-11-15", "2020-11-16", "2020-11-17", "2020-11-18", "2020-11-19", "2020-11-20", "2020-11-21", "2020-11-22", "2020-11-23", "2020-11-24", "2020-11-25", "2020-11-26", "2020-11-27", "2020-11-28", "2020-11-29", "2020-11-30"] }

问题陈述:

我想知道我应该做些什么改变所以在第二个JSON对象数组中,我可以得到下个月的日期。目前,我正在储存 娜达

{"current_month": ["2020-11-01", "2020-11-02", "2020-11-03", "2020-11-04", "2020-11-05", "2020-11-06", "2020-11-07", "2020-11-08", "2020-11-09", "2020-11-11", "2020-11-11", "2020-11-12", "2020-11-13", "2020-11-14", "2020-11-15", "2020-11-16", "2020-11-17", "2020-11-18", "2020-11-19", "2020-11-20", "2020-11-21", "2020-11-22", "2020-11-23", "2020-11-24", "2020-11-25", "2020-11-26", "2020-11-27", "2020-11-28", "2020-11-29", "2020-11-30"], 
"next_month": ["2020-12-01", "2020-12-02", "2020-12-03", "2020-12-04", "2020-12-05", "2020-12-06", "2020-12-07", "2020-12-08", "2020-12-09", "2020-12-11", "2020-12-11", "2020-12-12", "2020-12-13", "2020-12-14", "2020-12-15", "2020-12-16", "2020-12-17", "2020-12-18", "2020-12-19", "2020-12-20", "2020-12-21", "2020-12-22", "2020-12-23", "2020-12-24", "2020-12-25", "2020-12-26", "2020-12-27", "2020-12-28", "2020-12-29", "2020-12-30", "2020-12-31"] }

这就是我尝试过的:

这是我在Z行尝试过的,但它只在JSON对象数组中存储今天的日期。

$value->next_month = array_fill(0, ($next_month_days), date("Y-m-d")); //Z线

0 回复 | 直到 4 年前

jspit 4 年前

我认为你应该完全重新创建你的JSON字符串。从当月的第一天开始。循环始终运行,直到月份结束。接下来的一个月,整个事情又发生了。

$arr = $cur = [];
$date = date_create('first day of this month 00:00');
$startMonth = $month = $date->format('m');
while($startMonth == $month){
  $cur[] = $date->format('Y-m-d');
  $date->modify('+1 Day');
  $month = $date->format('m');
}
$arr["current_month"] = $cur;
$startMonth = $month;
$cur = [];
while($startMonth == $month){
  $cur[] = $date->format('Y-m-d');
  $date->modify('+1 Day');
  $month = $date->format('m');
}
$arr["next_month"] = $cur;
$jsonStr = json_encode($arr);

Technoh 4 年前

array_fill ,它至少用于填充数组的一部分 . 我建议使用一个简单的for循环:

$next_month_array = [];
$next_month = $month < 12 ? $month + 1 : 1;
$year = date('Y');

for($day_counter = 1; $day_counter <= $next_month_days; $day_counter++) {
  $next_month_array[] = "$year-$next_month-$day_counter";
}

$value->next_month = $next_month_array;