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如何确定SQL Server中表的主键?

  •  5
  • tekiegreg  · 技术社区  · 16 年前

    我希望在SQLServer2005中能够以某种方式使用表名作为输入来确定构成主键的所有字段。 sp_columns

    8 回复  |  直到 8 年前
        1
  •  7
  •   SIRHAMY Micky McQuade    9 年前

    SELECT i.name AS IndexName, 
        OBJECT_NAME(ic.OBJECT_ID) AS TableName, 
        COL_NAME(ic.OBJECT_ID,ic.column_id) AS ColumnName, 
        c.is_identity, c.user_type_id, CAST(c.max_length AS int) AS max_length, 
        CAST(c.precision AS int) AS precision, CAST(c.scale AS int) AS scale 
    FROM sys.indexes AS i 
    INNER JOIN sys.index_columns AS ic 
    INNER JOIN sys.columns AS c ON ic.object_id = c.object_id AND ic.column_id = c.column_id 
        ON i.OBJECT_ID = ic.OBJECT_ID AND i.index_id = ic.index_id 
    WHERE i.is_primary_key = 1 AND ic.OBJECT_ID = OBJECT_ID('dbo.YourTableNameHere')
    ORDER BY OBJECT_NAME(ic.OBJECT_ID), ic.key_ordinal
    
        2
  •  5
  •   Quill Remus Rusanu    8 年前

    事实上 主键 sys.key_constraints :

    select ic.key_ordinal, cl.name, ic.is_descending_key
    from sys.key_constraints c
    join sys.indexes i on c.parent_object_id = i.object_id
        and c.unique_index_id = i.index_id
    join sys.index_columns ic on ic.object_id = i.object_id
        and ic.index_id = i.index_id    
    join sys.columns cl on cl.object_id = i.object_id
        and ic.column_id = cl.column_id 
    where c.type = 'PK'
        and 0 = ic.is_included_column
        and i.object_id = object_id('<tablename>')
    order by ic.key_ordinal
    
        3
  •  4
  •   marc_s MisterSmith    16 年前

    select kcu.TABLE_SCHEMA, kcu.TABLE_NAME, kcu.CONSTRAINT_NAME, tc.CONSTRAINT_TYPE, kcu.COLUMN_NAME, kcu.ORDINAL_POSITION
      from INFORMATION_SCHEMA.TABLE_CONSTRAINTS as tc
      join INFORMATION_SCHEMA.KEY_COLUMN_USAGE as kcu
        on kcu.CONSTRAINT_SCHEMA = tc.CONSTRAINT_SCHEMA
       and kcu.CONSTRAINT_NAME = tc.CONSTRAINT_NAME
       and kcu.TABLE_SCHEMA = tc.TABLE_SCHEMA
       and kcu.TABLE_NAME = tc.TABLE_NAME
     where tc.CONSTRAINT_TYPE in ( 'PRIMARY KEY', 'UNIQUE' )
     order by kcu.TABLE_SCHEMA, kcu.TABLE_NAME, tc.CONSTRAINT_TYPE, kcu.CONSTRAINT_NAME, kcu.ORDINAL_POSITION;
    

    select s.name as TABLE_SCHEMA, t.name as TABLE_NAME
         , k.name as CONSTRAINT_NAME, k.type_desc as CONSTRAINT_TYPE
         , c.name as COLUMN_NAME, ic.key_ordinal AS ORDINAL_POSITION
      from sys.key_constraints as k
      join sys.tables as t
        on t.object_id = k.parent_object_id
      join sys.schemas as s
        on s.schema_id = t.schema_id
      join sys.index_columns as ic
        on ic.object_id = t.object_id
       and ic.index_id = k.unique_index_id
      join sys.columns as c
        on c.object_id = t.object_id
       and c.column_id = ic.column_id
     order by TABLE_SCHEMA, TABLE_NAME, CONSTRAINT_TYPE, CONSTRAINT_NAME, ORDINAL_POSITION;
    
        4
  •  3
  •   C B dkretz    8 年前

    SELECT * 
    FROM INFORMATION_SCHEMA.CONSTRAINT_COLUMN_USAGE
    WHERE table_name = 'your_table_name'
      AND constraint_name LIKE 'PK%'
    
        5
  •  2
  •   Austin Salonen gmlacrosse    16 年前
    select *
    from information_schema.Table_Constraints
    where Table_Name = @tableName
    

    MSDN Listing for Table Constraints .

        6
  •  1
  •   Alan    16 年前

    sp_help <table>
    

        7
  •  0
  •   JBrooks    16 年前

    sp_help myTable
    
        8
  •  0
  •   gloomy.penguin    13 年前

    select  cu.constraint_catalog, 
            cu.constraint_schema, 
            cu.table_name, 
            cu.constraint_name, 
            constraint_type, 
            column_name, 
            ordinal_position
    
    from    information_schema.key_column_usage cu 
    
            join information_schema.table_constraints as tc
                on tc.constraint_catalog = cu.constraint_catalog and 
                    tc.constraint_schema = cu.constraint_schema and 
                    tc.constraint_name   = cu.constraint_name and 
                    tc.table_name        = cu.table_name
    
    where   cu.table_name = 'table_name_goes_here'
    
    order by constraint_name, ordinal_position
    
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