如何用.net解析这个json?

我开始使用JSON.NET- http://james.newtonking.com/pages/json-net.aspx . 它是一个非常全面的JSON库,允许您做几乎任何事情。

System.Web.Extensions 装配

using System.Linq;
using System.Collections;
using System.Collections.Generic;
using System.Web.Script.Serialization;

class Program
{
    public class Test
    {
        public string Id { get; set; }
        public string Answer { get; set; }
    }

    static void Main(string[] args)
    {
        string data ="[[\"9\",\"3\"],[\"8\",\"4\"],[\"7\",\"4\"],[\"6\",\"5\"]]";
        List<Test> tests = 
            Array.ConvertAll<ArrayList, Test>(
                new JavaScriptSerializer()
                    .Deserialize<ArrayList>(data)
                        .OfType<ArrayList>().ToArray(), 
               (item) =>
               {
                   return new Test()
                   {
                       Id = (string)item[0],
                       Answer = (string) item[1]
                   };
               }).ToList();
    }
}

罗夫,HTH

        Dictionary<int, int> jsonValues = new Dictionary<int, int>();

        string data = "[[\"9\",\"3\"],[\"8\",\"4\"],[\"7\",\"4\"],[\"6\",\"5\"],[\"5\",\"6\"],[\"4\",\"4\"],[\"3\",\"4\"]]";

        string[] items = data.Split(new string[]{"\"],[\""}, StringSplitOptions.RemoveEmptyEntries);

        foreach (string str in items)
        {
            string[] intVals = str
                .Replace("\"", "")
                .Replace("[", "")
                .Replace("[", "")
                .Replace("]", "").Split(',');

            jsonValues.Add(int.Parse(intVals[0]), int.Parse(intVals[1]));
        }

        // test print:
        foreach (KeyValuePair<int,int> kvp in jsonValues)
        {
            System.Diagnostics.Debug.WriteLine(
                "ID:" + kvp.Key + " val:" + kvp.Value );
        }

顺便说一句因为您正在提取名称-值对,所以我只使用int/int字典来保存数据。

        var val = "[[\"9\",\"3\"],[\"8\",\"4\"],[\"7\",\"4\"],[\"6\",\"5\"],[\"5\",\"6\"],[\"4\",\"4\"],[\"3\",\"4\"]]";

        var result = val.ToCharArray()
            .Where(itm => Char.IsDigit(itm))
            .Select((itm, index) => new {c = int.Parse(itm.ToString()),index = index + 1})
            .GroupBy(itm => itm.index % 2 == 0 ? itm.index - 1 : itm.index)
            .Select(itm => new KeyValuePair<int, int>(itm.ElementAt(0).c, itm.ElementAt(1).c));

我认为最简单的方法是以下代码:

using System.Collections.Generic;
using System.IO;
using System.Runtime.Serialization.Json;
using System.Text;

namespace JsonParser
{
    class Program
    {
        static void Main(string[] args)
        {
            string data = "[[\"9\",\"3\"],[\"8\",\"4\"],[\"7\",\"4\"],[\"6\",\"5\"],[\"5\",\"6\"],[\"4\",\"4\"],[\"3\",\"4\"]]";
            var stream = new MemoryStream(new ASCIIEncoding().GetBytes(data));
            var deserializer = new DataContractJsonSerializer(typeof(List<List<string>>));
            var result = (List<List<string>>)deserializer.ReadObject(stream);
        }
    }
}

此外,您还必须记住添加对以下DLL的引用:

• System.ServiceModel.Web

下面是一个使用RegEx的解决方案

string data = "[[\"9\",\"3\"],[\"8\",\"4\"],[\"7\",\"4\"],[\"6\",\"5\"],[\"5\",\"6\"],[\"4\",\"4\"],[\"3\",\"4\"]]";

var pairs = (from Match m in Regex.Matches(data, "\"[0-9]\"\\,\"[0-9]\"") 
             select m.Value.Split(',')).ToDictionary(d => d[0], d => d[1]);

添加:如果希望结果值为int而不是字符串,则可以这样做

var pairs = (from Match m in Regex.Matches(data, "\"[0-9]\"\\,\"[0-9]\"") 
        select m.Value.Split(','))
       .ToDictionary(d => Int32.Parse(d[0].Replace("\"", "")), 
                     d => Int32.Parse(d[1].Replace("\"", "")));

在Silverlight中,有System.Json.dll使Json解析非常容易。有人说要把它放到.NET4.0中,但不确定它是否发生过。